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GrogVix [38]
3 years ago
15

The sequence an = 1/2 (2)^(n - 1) is graphed below:

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0
Is there a photo with this
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Shannon Perfumeries sells two fragrances. The table contains the price corresponding to the number of bottles of fragrance A. Bo
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<span>Table
Bottles Price($)
3           78
6           156
9           234

From that you can find the unit price: 78 / 3 = 156 / 6 = 234 / 9 = 26.

That means that the unit rate of this fragance is $26.

If you call x the number of bottles the equation is

Price = unit rate * number of bottles = 26x.

Now compare this information with that on your graph to compare the unit rates.

This can help you fo find the unit rate in from your grpah: the unit rate is the slope of the line =

[change in y-coordinate] / [change in the x-coordinate]
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During summer, when the snow melts, the water level of the Yukon River increases. If the water level of the river increased by 7
kondaur [170]

Answer:

13 centimeters per day.

Step-by-step explanation:

We have been given that during summer, the water level of the river increased by 78 centimeters in 6 days. We are asked to find the water level increase rate in centimeters per day.

To find the water level increase rate per day, we will divide total increase by total days as:

\text{Water level increase rate per day}=\frac{78\text{ cm}}{6\text{ days}}

\text{Water level increase rate per day}=\frac{13\text{ cm}}{\text{ day}}

Therefore, the water level increase rate is 13 centimeters per day.

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3 years ago
Find sin θ, cot θ, and csc θ, where θ is the angle shown in the figure.
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Step-by-step explanation:

everything can be found in the picture

8 0
3 years ago
Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
3 years ago
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