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Verdich [7]
3 years ago
5

How many grams of magnesium acetate are in 8.95x10^23 formula units?

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

211.63 g.

Explanation:

  • Particles could refer to atoms, molecules, formula units.
  • <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:  </u></em>

1.0 mole → 6.022 x 10²³ molecules.

??? mole → 8.95 x 10²³ molecules.

  • The no. of moles of magnesium acetate = (8.95 x 10²³ molecules) (1.0 mole) / (6.022 x 10²³ molecules) = 1.486 mol.

∴ The grams of magnesium acetate are in 8.95 x 10²³ formula units = n x molar mass = (1.486 mol)(142.394 g/mol) = 211.63 g.

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Molar mass:

KCl = 74.55 g/mol

KClO3 = 122. 55 g/mol

  <span>Calculation of the mass of KClO3 :</span>

<span>2 KClO3 =  2 KCl + 3 O2</span>

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1 mole KClO3 ---------------------- 122.55 g
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moles KClO3 = 42.082 * 1 / 122.55

moles KClO3 = 42.082 / 122.55

=> 0.343 moles of KClO3


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