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4 years ago

What is the difference between a job and a profession

1 answer:

4 0

Job is the activity performed in exchange for monetary value. It is often short-term and only done as a person requires money to live. A profession is a vocation based on specialized educational training. Jobs is a narrower concept and do not make a significant impact on a person's life or society

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A charge of 11.748 nC is uniformly distributed along the x-axis from −2 m to 2 m . What is the electric potential (relative to z

svp [43]

Answer:

electric potential = 22.36 volt

Explanation:

given data

charge Q = 11.748 nC

distance d = 5 - 2 = 3 m

length = 2 + 2 = 4 m

Coulomb constant = 8.98755 × 109 N·m²/C ²

solution

electric potential is express as

electric potential = $\frac{Q}{4\pi \epsilon _o L}$ $ln(1+\frac{L}{d})$ ..............1

electric potential = $\frac{KQ}{L} ln(1+\frac{L}{d})$

put here value

electric potential = $\frac{8.98755\times 10^9\times 11.748\times 10{-9}}{4} ln(1+\frac{4}{3})$

electric potential = 22.36 volt

6 0

3 years ago

Finally you will implement the full Pegasos algorithm. You will be given the same feature matrix and labels array as you were gi

Diano4ka-milaya [45]

Answer:

In[7] def pegasos(feature_matrix, labels, T, L):

"""

let learning rate = 1/sqrt(t),

where t is a counter for the number of updates performed so far (between 1 and nT inclusive).

Args:

feature_matrix - A numpy matrix describing the given data. Each row

represents a single data point.

labels - A numpy array where the kth element of the array is the

correct classification of the kth row of the feature matrix.

T - the maximum number of times that you should iterate through the feature matrix before terminating the algorithm.

L - The lamba valueto update the pegasos

Returns: Is defined as a tuple in which the first element is the final value of θ and the second element is the value of θ0

"""

(nsamples, nfeatures) = feature_matrix.shape

theta = np.zeros(nfeatures)

theta_0 = 0

count = 0

for t in range(T):

for i in get_order(nsamples):

count += 1

eta = 1.0 / np.sqrt(count)

(theta, theta_0) = pegasos_single_step_update(

feature_matrix[i], labels[i], L, eta, theta, theta_0)

return (theta, theta_0)

In[7] (np.array([1-1/np.sqrt(2), 1-1/np.sqrt(2)]), 1)

Out[7] (array([0.29289322, 0.29289322]), 1)

In[8] feature_matrix = np.array([[1, 1], [1, 1]])

labels = np.array([1, 1])

T = 1

L = 1

exp_res = (np.array([1-1/np.sqrt(2), 1-1/np.sqrt(2)]), 1)

pegasos(feature_matrix, labels, T, L)

Out[8] (array([0.29289322, 0.29289322]), 1.0)

Explanation:

In[7] def pegasos(feature_matrix, labels, T, L):

"""

let learning rate = 1/sqrt(t),

where t is a counter for the number of updates performed so far (between 1 and nT inclusive).

Args:

feature_matrix - A numpy matrix describing the given data. Each row

represents a single data point.

labels - A numpy array where the kth element of the array is the

correct classification of the kth row of the feature matrix.

T - the maximum number of times that you should iterate through the feature matrix before terminating the algorithm.

L - The lamba valueto update the pegasos

Returns: Is defined as a tuple in which the first element is the final value of θ and the second element is the value of θ0

"""

(nsamples, nfeatures) = feature_matrix.shape

theta = np.zeros(nfeatures)

theta_0 = 0

count = 0

for t in range(T):

for i in get_order(nsamples):

count += 1

eta = 1.0 / np.sqrt(count)

(theta, theta_0) = pegasos_single_step_update(

feature_matrix[i], labels[i], L, eta, theta, theta_0)

return (theta, theta_0)

In[7] (np.array([1-1/np.sqrt(2), 1-1/np.sqrt(2)]), 1)

Out[7] (array([0.29289322, 0.29289322]), 1)

In[8] feature_matrix = np.array([[1, 1], [1, 1]])

labels = np.array([1, 1])

T = 1

L = 1

exp_res = (np.array([1-1/np.sqrt(2), 1-1/np.sqrt(2)]), 1)

pegasos(feature_matrix, labels, T, L)

Out[8] (array([0.29289322, 0.29289322]), 1.0)

6 0

3 years ago

Using the Breguet range and endurance equation, estimate the amount of kerosene

love history [14]

The amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

<h3>What is Breguet equation?</h3>

Breguet equation is used to determine the range of airplane fly in some specified set of parameters.

$R=\dfrac{h_f}{g}\dfrac{L}{D}\times \eta \ln \left(\dfrac{W_{initial}}{W_{final}}\right)$

Here, (L/D) is lift to drag ratio,<em> g</em> is gravitation acceleration,<em> h </em>is height and <em>W</em> is weight.

The weight of aircraft is 10 metric tons (this is the dry weight that includes passengers and cargo) The distance of 5,000 [km], with velocity at 300 [m/s] from Boston to Los Angeles has to be cover by the airplane.

The initial weight is 10 metric tons or 10000 kg. Thus, the final weight with total fuel burn is,

$W_{final}=W_{initial}-W_{fuel}\\W_{final}=1-\dfrac{W_{fule}}{W_{initial}}$

The lift-to-drag ratio is 15 and the overall efficiency is 0.3, The standard air density at an altitude of approximately 6,000 [m] is half.

Thus, put the values, in above formula,

$5000=\dfrac{6000}{9.81}(15)\times(0.3) \ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)\\$

$\ln \left(\dfrac{10000}{1-\dfrac{W_{fuel}}{10000}}}\right)=1.8167\\\ln \left(\dfrac{1}{10000-W_{fuel}}}\right)=1.8167$

Solving this equation, we get,

$W_{fuel}=10000\rm\; kg\\$

Thus, the amount of kerosene fuel needed for an aircraft weighing 10 metric tons to fly from Boston to Los Angeles, assuming a distance of 5,000 [km] is 10000 kg.

Learn more about the Breguet equation here:

brainly.com/question/15218094

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7 0

2 years ago

¿Qué son alimentos funcionales?

Mnenie [13.5K]

DescripciónAlimentos funcionales son aquellos alimentos que son elaborados no solo por sus características nutricionales sino también para cumplir una función específica como puede ser el mejorar la salud y reducir el riesgo de contraer enfermedades

4 0

3 years ago

As resistors are added in series to a circuit, the total resistance will

olganol [36]

The equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

<h3>
What is resistance?</h3>

Resistance is the obstruction offered whenever the current is flowing through the circuit.

So the equivalent resistance is when three resistances are connected in series. When the resistances are connected in series then the voltage is different and the current remain same in each resistance.

V eq = V₁ + V₂ + V₃

IReq = IR₁ + IR₂ + IR₃

Req = R₁ + R₂ + R₃

Therefore the equivalent of the resistance connected in the series will be Req=R₁+R₂+R₃.

To know more about resistance follow

brainly.com/question/24858512

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8 0

2 years ago