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jarptica [38.1K]
3 years ago
13

Classify the carbohydrate tagatose by both the carbonyl group and the number of carbon atoms. D-tagatose is sugar with six carbo

n atoms. The Fischer projection shows C1 is achiral with one OH group, C2 is the location of the carbonyl, C3 and C4 have OH groups on the left, C5 has an OH groups on the right, and C6 is achiral. Enter the classification (e.g., aldotriose).
Chemistry
1 answer:
Bingel [31]3 years ago
6 0

Answer:

Hexose category and ketohexose category

Explanation:

The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category

Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category

Attached below is the remaining part of the solution

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If 12.5 grams of strontium hydroxide is reacted with 150 mL of 3.5 M carbonic acid, identify the limiting reactant.
vesna_86 [32]

Answer:

Sr(OH)2

Explanation:

We'll begin by calculating the number of mole of carbonic acid in 150mL of 3.5 M carbonic acid solution. This is illustrated below:

Molarity = 3.5M

Volume = 150mL = 150/1000 = 0.15L

Mole of carbonic acid, H2CO3 =..?

Mole = Molarity x Volume

Mole of carbonic acid, H2CO3 = 3.5 x 0.15 = 0.525 mole.

Next, we shall convert 0.525 mole of carbonic acid, H2CO3 to grams.

Mole of H2CO3 = 0.525 mole

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 =..?

Mass = mole x molar mass

Mass of H2CO3 = 0.525 x 62 = 32.55g

Next, we shall write the balanced equation for the reaction. This is given below:

Sr(OH)2 + H2CO3 → SrCO3 + 2H2O

Next, we shall determine the mass of Sr(OH)2 and H2CO3 that reacted from the balanced equation. This is illustrated below:

Molar mass of Sr(OH)2 = 88 + 2(16 + 1) = 88 + 2(17) = 122g/mol

Mass of Sr(OH)2 from the balanced equation = 1 x 122 = 122g

Molar mass of H2CO3 = (2x1) + 12 + (16x3) = 62g/mol.

Mass of H2CO3 from the balanced equation = 1 x 62 = 62g.

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Finally, we shall determine the limiting reactant as follow:

From the balanced equation above, 122g of Sr(OH)2 reacted with 62g of H2CO3.

Therefore, 12.5g of Sr(OH)2 will react with = (12.5 x 62)/122 = 6.35g.

We can see evidently from the calculations made above that it will take 6.35g out 32.55g of H2CO3 to react with 12.5g of Sr(OH)2. Therefore, Sr(OH)2 is the limiting reactant and H2CO3 is the excess reactant

5 0
3 years ago
Read 2 more answers
How do similarities in the bones of humans dolphins and horse and
Andrej [43]
It provides evidence that each organism is related and similar in each way, leading to the conclusion of a common ancestor.<span />
6 0
3 years ago
What is the atom inventory for the following equation after it is properly balanced? ____NaOH + ____CuCl2 Imported Asset ____NaC
faltersainse [42]

Answer:

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2;

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

Explanation:

NaOH + CuCL2 —> NaCl + Cu(OH)2

The balanced equation can be achieved by doing the following:

There are 2 oxygen and 2 hydrogen atom on the right side. This is balanced by putting 2 in front of NaOH as shown below:

2NaOH + CuCL2 —> NaCl + Cu(OH)2

This makes Na to be unbalanced. Now to balance Na, put 2 in front of NaCl as illustrated below

2NaOH + CuCL2 —> 2NaCl + Cu(OH)2

Now the equation is balanced.

Reactants: Na = 2, O = 2, H = 2, Cu = 1, Cl = 2

Products: Na = 2, Cl = 2, Cu = 1, O = 2, H = 2

4 0
3 years ago
Water vapor is not usually seen.
xeze [42]

Answer:

True

Explanation:

Water vapor is totally invisible.

Without it, there would be no clouds or rain or snow, since all of these require water vapor in order to form. All of the water vapor that evaporates from the surface of the Earth eventually returns as precipitation - rain or snow.

Helped by the <u><em>One</em></u> & <u><em>Only</em></u> <u><em>#QUEEN</em></u> aka <u><em>#DRIPPQUEENMO </em></u>

<u><em>Hoped this helped! :)</em></u>

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3 years ago
What are the two cell division stages in the mitotic phase of the cell cycle?
Ugo [173]
Cytokinesis and telophase!
6 0
3 years ago
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