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worty [1.4K]
2 years ago
14

Calculate the percentage of zinc I zncl2

Chemistry
1 answer:
Murrr4er [49]2 years ago
4 0

Answer:

47.8 %

Explanation:

Ar of Zn = 65

Mr of ZnCl2 = 65 + (2 * 35.5)

= 65+ 71

= 136

Percentage Composition

= ( Ar of element × No of atom in formula ) / Mr of compound * 100 %

% composition of Zn = ( 65*1 )/ 136 × 100 %

= 47.7941...

= 47.8 % ( 3 s.f )

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What design element of an astronaut's spacesuits protects him or her from micrometeoroids, which are tiny bits of space debris t
leonid [27]

Answer:

Tough outer shell

Explanation:

Three types of space suits based on their purpose are IVA (Intravehicular activity), EVA (extravehicular activity), and IEVA (intra/extravehicular activity)

Space suits have an outer layer known as the Integrated Thermal Micrometeoroid Garment also known as the TMG or ITMG

The functions of the TMG includes the provision of an insulation medium to the wearer of the suit thereby preventing loss of heat and keeping the wearer warm, protect the wearer from solar radiation which are harmful as well as from Micrometeoroid and debris orbiting in space known as MMOD

The outermost layer of the EMU TMG suits is white Ortho-Fabric that consists of Nomex, Kevlar and Gore-Tex, making it fire resistant, very strong and very tough, and water proof as well as breathable.

3 0
3 years ago
A cylinder of compressed gas has a volume of 350 ml and a pressure of 931 torr. What volume in Liters would the gas occupy if al
hodyreva [135]

Answer:

0.384\ \text{L}

Explanation:

P_1 = Initial pressure = 931 torr = 931\times \dfrac{101.325}{760}=124.12\ \text{kPa}

P_2 = Final pressure = 113 kPa

V_1 = Initial volume = 350 mL

V_2 = Final volume

From the Boyle's law we have

P_1V_1=P_2V_2\\\Rightarrow V_2=\dfrac{P_1V_1}{P_2}\\\Rightarrow V_2=\dfrac{124.12\times 350}{113}\\\Rightarrow V_2=384.44\ \text{mL}=0.384\ \text{L}

The volume the gas would occupy is 0.384\ \text{L}.

3 0
3 years ago
True or false: Energy and matter are the same thing.
kenny6666 [7]

Answer:

yes they are same thing by E=MC^2 EINSTEIN'S EQUATION

5 0
3 years ago
Read 2 more answers
PLEASE HELP WILL GIVE BRAINLYIST TO FIRST PERSON
kolezko [41]

Answer:

1) Weak base.

2) Weak acid.

Explanation:

<em>1) Which would have a lower pH, a 0.1 M solution of a strong base or a weak base? Why?</em>

  • For bases:

Solution with lower pH means that the solution has a lower basic character.

While solution with higher pH means that the solution has a higher basic character.

When we have a 0.1 M solution of a strong base or a weak base, the weak base will have a lower pH because it is not completely dissociated to produce OH⁻ ions.

While, strong base dissociates completely to produce OH⁻ ions, so it will has higher basic character and thus has a higher pH value.

So, weak base will have the lower pH value.

<em>2) Which would have a higher pH, a 0.1 M solution of a strong acid, or a weak acid? Why?</em>

<em></em>

  • For Acids:

Solution with lower pH means that the solution has a higher acidic character.

While solution with higher pH means that the solution has a lower acidic character.

When we have a 0.1 M solution of a strong acid or a weak acid, the weak acid will have a higher pH because it is not completely dissociated to produce H⁺ ions, so it has a lower acidic character.

While, strong acid dissociates completely to produce H⁺ ions, so it will has higher acidic character and thus has a lower pH value.

So, weak acid will have the higher pH value.

5 0
3 years ago
2. When heated above 500 ºC, potassium nitrate decomposes according to the equation below. 4KNO3 2K2O + 2N2 + 5O2A.If oxygen is
AysviL [449]

Answer:

(a) The rate of formation of K2O is 0.12 M/s.

The rate of formation of N2 is also 0.12 M/s

(b) The rate of decomposition of KNO3 is 0.24 M/s

Explanation:

(a) From the equation of reaction, the mole ratio of K2O to O2 is 2:5.

Rate of formation of O2 is 0.3 M/s

Therefore, rate of formation of K2O = (2×0.3/5) = 0.12 M/s

Also from the equation of reaction, mole ratio of N2 to O2 is 2:5.

Rate of formation of N2 = (2×0.3/5) = 0.12 M/s

(b) From the equation of reaction, mole ratio of KNO3 to O2 is 4:5.

Therefore, rate of decomposition of KNO3 = (4×0.3/5) = 0.24 M/s

3 0
3 years ago
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