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Vlada [557]
2 years ago
15

2 Zn + 2HNO2-> 2 ZN(NO2)2 + H2

Chemistry
1 answer:
Aliun [14]2 years ago
8 0
It 6.8 so there you go And this answer is Long because I just need points lol
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How many moles of mercury(II) oxide, HgO, are needed to produce 125 g of oxygen, O2? How many moles of mercury is produced?​
iren2701 [21]

Answer: 7.81 mol HgO (How many moles of mercury(II) oxide, HgO, are needed to produce 125 g of oxygen, O2?)

Explanation:

7 0
2 years ago
A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 4250 mL of water at 2
Assoli18 [71]

Answer:

The specific heat of copper is 0.385 J/g°C

Explanation:

A 85.2 g copper bar was heated to 221.32 degrees Celsius and placed in a coffee cup calorimeter containing 425 mL of water at 22.55 degrees Celsius. The final temperature of the water was recorded to be 26.15 degrees Celsius. What is the specific heat of the copper?

Step 1: Data given

Mass of copper = 85.2 grams

Temperature of copper = 221.32 °C

Volume of water = 425 mL

Temperature of water = 22.55 °C

Final temperature = 26.15 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculat the specific heat of copper

Heat lost = heat gained

Q = m*c*ΔT

Qcopper = -Qwater

m(copper)*c(copper)*ΔT(copper) = - m(water) * c(water) * ΔT(water)

⇒ m(copper) = 85.2 grams

⇒ c(copper) = TO BE DETERMINED

⇒ ΔT(copper) = the change in temeprature = T2 -T1 = 26.15 -221.32 = -195.17 °C

⇒ m(water) = The mass of water = 425 mL * 1g/mL = 425 grams

⇒ c(water) = The specific heat of water = 4.184 J/g°C

⇒ ΔT(water) = The change of temperature of water = 26.15 - 22.55 = 3.6

85.2 * c(copper) * (-195.17) = -425 * 4.184 * 3.6

c(copper) = 0.385 J/g°C

The specific heat of copper is 0.385 J/g°C

(Note, The original question says the volume of the water is 4250 mL. IF this is not an error, the specific heat of copper is 3.85 J/g°C (10x higher than the normal value).

8 0
3 years ago
What's the difference between gold and other metals
Zanzabum
Well, gold is way different form other say for instance what if you get a really good ring not to expensive or cheap, but its in between those characteristics what if u get a gold ring to compare now one might tarnish or fade, but if you really look at it that gold one will not it really all dependents on what metals your talking about cause all metals aren't the same some fade and some don't . Also the oxygen level is weak for other metals, but gold it different it can still keeps its shine .

 - That's the best explanation i can give IF ITS NOT ENUH OR NOT RIGHT JUH COMMENT BELOWW↓↓ I WILL THINK OF SOMEThING ELSE THANKS! YOU HAVE A GREAT DAYY .
5 0
3 years ago
Volcanoes emit much hydrogen sulfide gas, h2s, which reacts with the oxygen in the air to form water and sulfur dioxide, so2. ev
liq [111]

Answer: There will be 131.3 tons of SO_{2} that will be generated.


Explanation : We have the data as 72 tons of H_{2}S, O_{2} is 101 tons and H_{2}O as 38 tons.


Conversion of 1 ton to kg will be approximately 907.2 Kg


We have to convert the given data of tons into kg for all;


So, moles of H_{2}S = (72 tons X 907.2 Kg/ton X 1000 g/Kg) / (34.082 g/ mol) = 1.916 X 10^{6} moles

Now, moles of O_{2} = (101 tons X 907.2 Kg/ton X 1000 g/Kg) / (32 g/mol) = 2.80 X10^{6} moles

And, H_{2}O = (38 tons X 907.2 Kg/ton X 1000 g/Kg) / (18.016 g/mol)

= 1.03 X 10^{6} moles


Now, we have to calculate the moles of H_{2}S

so, 1.916 X 10^{6} moles / 2 moles of H_{2}S = 958 X 10^{3}


Now, for O_{2} ;

So, 2.80 X10^{6} moles / 3 moles of O_{2} = 933.3 X 10^{3} moles


Here, we can see that O_{2} is acting as a limiting reactant.


Now, moles of SO_{2} = 2.80 X10^{6} X (2 moles of SO_{2} / 3 moles of O_{2}) = 1.86 X 10^{6}


Now converting this into mass,


Mass = Moles X Molar Mass

Mass = 1.86 X 10^{6} X (64.066 g/mol X 10^{-3} kg/g) X (1 ton / 907.2 Kg)

= 131.3 tons of SO_{2}

7 0
3 years ago
Read 2 more answers
John and his wife are celebrating their first wedding anniversary. Their dinner consists of 55 grams of carbohydrates, 36 grams
nika2105 [10]

Answer: 733 kcal

Explanation:

According to a system used to calculate the available energy of foods, we have the following data:

  • protein has 4 kcal/g
  • carbohydrates has 4 kcal/g
  • fat has 9 kcal/g
  • alcohol has 7 kcal/g

So, we are told Jhon and his wife's dinner has:

  • 55 g of carbohydrates
  • 36 g of protein
  • 27 g of fat
  • 18 g of

Now we have to multiply these values by the kilocalories:

  • (55 g of carbohydrates)(4 kcal/g)=220 kcal  
  • (36 g of protein)(4 kcal/g)=144 kcal
  • (27 g of fat)(9 kcal/g)=243 kcal
  • (18 g of alcohol)(7 kcal/g)=126 kcal

Then we have to sum all, giving the following result:

<h2>733 kcal</h2>
4 0
3 years ago
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