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3 years ago

13

When the air inside a hot air balloon is heated, it expands and takes up a larger volume. As a result, it floats higher into the

sky. What else happens to the air inside the balloon as it is heated?

1 answer:

pav-90 [236]3 years ago

6 0

I believe it becomes gasses the hotter it gets

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Which method is used to obtain petrol from petroleum?

kotykmax [81]

Explanation:

fractional distillation method is used to obtain petrol from petroleum...

hope it helps

6 0

2 years ago

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PLEASE HELP DUE TODAY 55 POINTS

Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1$ = initial pressure of gas = 0.974 atm

$P_2$ = final pressure of gas = 0.993 atm

$V_1$ = initial volume of gas = 27.5 mL

$V_2$ = final volume of gas = ?

$T_1$ = initial temperature of gas = $22.0^oC=273+22.0=295K$

$T_2$ = final temperature of gas = $15.0^oC=273+15.0=288K$

Now put all the given values in the above equation, we get:

$\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}$

$V_2=26.3mL$

Therefore, the final volume of gas will be, 26.3 mL

3 0

3 years ago

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Which of the following is the name of the process scientists use to gain

kobusy [5.1K]

Scientific method

Explanation:

The scientific method is the name of the process scientists use to gain knowledge about the physical world.

The scientific method is a systematic approach into the study of nature. It follows the following processes:

Detailed observation
Asking of question
Formulation of hypothesis
Experimentation
Analysis and interpretation
Conclusion

learn more:

Experiment brainly.com/question/1621519

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8 0

3 years ago

1.How many mL of 0.401 M HI are needed to dissolve 5.97 g of BaCO3?

garri49 [273]

Answer:

The answer to your question is:

1.- volume = 0.151 l or 151 ml

2.- 0.241 l or 241 ml of NaOH

Explanation:

1.-

Data

V = ? HI = 0.401 M

BaCO3 = 5.97 g

2HI(aq) + BaCO3(s) ⇒ BaI2(aq) + H2O(l) + CO2(g)

MW BaCO3 = 137 + 12 + 48 = 197 g

197 g of BaCO3 ----------------- 1 mol

5.97 g ----------------- x

x = (5.97 x 1) /197

x = 0.03 mol of BaCO3

2 moles of HI ---------------- 1 mol of BaCO3

x ---------------- 0.03 mol of BaCO3

x = (0.03 x 2) / 1

x = 0.060 mol of HI

Molarity = moles / volume

volume = moles / molarity

volume = 0.060 / 0.401

volume = 0.151 l or 151 ml

2.-

V = ? NaoH 0.757 M

Co⁺² Volume = 167 ml 0.548 M

CoSO4(aq) + 2NaOH(aq) ⇒ Co(OH)2(s) + Na2SO4(aq)

Moles of Co = Molarity x volume

Moles of Co = 0.548 x 0.167

Moles of Co = 0.092

1 mol of CoSO4 -------------- 2 moles of NaOH

0.092 moles --------------- x

x = (0.092 x 2) /1

x = 0.183 moles of NaOH

Volume of NaOH = moles / molarity

= 0.183 / 0.757

= 0.241 l or 241 ml of NaOH

6 0

3 years ago

Most reactions speed up when

miss Akunina [59]

For a reaction to occur, there should be mobility of ions in reactant side.
If the reactant is larger, its mobility will be lesser than that of smaller ones.
So reactants smaller in size have higher mobility which makes reaction faster.

Hence D is the correct option.

Hope this helps, have a great day/night ahead!

7 0

3 years ago

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