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8_murik_8 [283]
3 years ago
6

Evidence for past events in Earth's ancient history are provided by:

Chemistry
1 answer:
g100num [7]3 years ago
7 0
Rocks and the fossils within them!
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For the reaction represented by the equation 2H2 + O2→ 2H2O, how many grams of water can be produced from 6.0 grams of O2?
leonid [27]

Answer:

a. 6 grams

b. 108 grams

c. 2 grams

d. 54 grams

5 0
3 years ago
Water molecules are listed from a to b to c in
dedylja [7]
It is from least to greatest

5 0
3 years ago
Will a precipitate form when 20.0 ml of 0.10 M Ba(NOxaq) and 50.0 mL of 0.10 M NaCO(aq) are mixed together?
Tom [10]

Answer:

B. Q > K precipitate will form

Explanation:

The reaction is;

Ba(NO3)2(aq) + Na2CO3(aq) ------> BaCO3(s) + 2NaNO3(aq)

Hence the reaction could form a precipitate of BaCO3.

Number of moles of carbonate ions = 50/1000 * 0.10 M =  5 * 10^-3 moles

Number of moles of Barium ions = 20/1000 * 0.10 M = 2 * 10^-3 moles

Total volume after reaction = 20ml + 50ml = 70 ml or 0.07 L

Molarity Barium ions = 5 * 10^-3 moles/ 0.07 L = 0.07 M

Molarity carbonate ions = 2 * 10^-3 moles/ 0.07 L =0.03 M

Q = [Ba^2+] [CO3^2-] = 0.07 * 0.03 = 2.1 * 10^-3

But K = 2.58  ×  10 ^− 9

We can clearly see that Q>K therefore precipitate will form

5 0
3 years ago
Draw the alkyne formed when 2,3-dichloropentane is treated with an excess of strong base such as sodium amide.
Xelga [282]
Hi! Thank you for posting your question here at Brainly. I hope I would be able to help you with my answer.

When an alkyne such as 2,3-dichloropentane is treated with excess sodium amide, a two-step elimination reaction will happen. The reaction would then yield the final product in the form of 2-pentyne. Its structure is shown in the attached image.

8 0
4 years ago
Read 2 more answers
If 9.5 atms of pressure were increased to 25 atms of pressure, what would be the final volume
nordsb [41]

Answer:

The final volume of the gas is 36.1 L.

Explanation:

Given:

Initial pressure of the gas is, P_1=9.5\ atm

Final pressure of the gas is, P_2=25\ atm

Initial volume of the gas is, V_1=95\ L

Final volume of the gas is, V_2=?

Here, we shall use Boyle's Law which states that for a process under constant temperature, the pressure of the gas changes inversely with the change in volume.

Here, the pressure is increased. So, the volume of the gas is decreased.

Therefore, as per Boyle's Law:

P_1V_1=P_2V_2\\9.5\times 95=25V_2\\902.5=25V_2\\V_2=\frac{902.5}{25}\\V_2=36.1\ L

So, the final volume of the gas is 36.1 L.

4 0
3 years ago
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