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3 years ago

11

if a moose were chasing you through the woods its enormous mass would be very threatening but if you zigzagged then it great mas

s would be to your advantage explain why

1 answer:

worty [1.4K]3 years ago

3 0

Because you have the same mass as the mousse

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Find the solution set of x + y = 5, 2 x - y = 7

STALIN [3.7K]

X + y = 5
x = 5 - y

2x - y = 7
2(5-y) - y = 7
10 - 2y - y = 7
10 - 3y = 7
10 - 7 = 3y
3 = 3y
y = 1

x + y = 5
x + 1 = 5
x = 5 - 1
x = 4

4 0

3 years ago

In the real world, How does conduction, convection and radiation work? (Examples needed) (WILL MARK BRAINLIST)

Naddik [55]

Conduction: someone burning their hand by placing their hand on a hot stove.

Convection: Food cooking in an oven.

Radiation: The heat we feel from the sun.

3 0

3 years ago

Identify how scientists use radioactive isotopes by selecting the best answers from the drop-down menus. Archaeologists use radi

salantis [7]

Answer:

Archaeologist use radioactive isotopes to determine the ages of various objects, rocks and materials. This is called radioactive dating. Radioactive isotope Carbon-14 is widely used for this dating process.

Scientists use radioactive isotopes in agriculture to monitor or study the uptake and use of essential nutrients by plants from the soil. This helps to determine viability, productivity and nutritious ability of the plants on a piece of land.

Geologists use radioactive isotopes to trace leaks in underground water storage, pipes. Radioactive isotopes are effective tracers because their radioactivity can be easily detected.

6 0

3 years ago

Read 2 more answers

The specific heat of water is 4.18 J/gºC. How many Joules of

densk [106]

Answer:

Q = 59565 [J]

Explanation:

In order to calculate the amount of thermal energy needed we must use the following equation.

$Q=m*C_{p}*(T_{i}-T_{f})$

where:

m = mass = 150 [g]

Cp = 4.18 [J/g*°C]

Tfinal = 5 [°C]

Tinitial = 100 [°C]

Now replacing:

$Q=150*4.18*(100-5)\\Q=59565[J]$

8 0

2 years ago

A ball is thrown upward with a speed of 28.2 m/s.A. What is its maximum height?B. How long is the ball in the air?C. When does t

Ede4ka [16]

Answer:

(A) The maximum height of the ball is 40.57 m

(B) Time spent by the ball on air is 5.76 s

(C) at 33.23 m the speed will be 12 m/s

Explanation:

Given;

initial velocity of the ball, u = 28.2 m/s

(A) The maximum height

At maximum height, the final velocity, v = 0

v² = u² -2gh

u² = 2gh

$h = \frac{u^2}{2g}\\\\h = \frac{(28.2)^2}{2*9.8}\\\\h = 40.57 \ m$

(B) Time spent by the ball on air

Time of flight = Time to reach maximum height + time to hit ground.

Time to reach maximum height = time to hit ground.

Time to reach maximum height is given by;

v = u - gt

u = gt

$t = \frac{u}{g}$

Time of flight, T = 2t

$T = \frac{2u}{g}\\\\ T = \frac{2*28.2}{9.8}\\\\ T = 5.76 \ s$

(C) the position of the ball at 12 m/s

As the ball moves upwards, the speed drops, then the height of the ball when the speed drops to 12m/s will be calculated by applying the equation below.

v² = u² - 2gh

12² = 28.2² - 2(9.8)h

12² - 28.2² = - 2(9.8)h

-651.24 = -19.6h

h = 651.24 / 19.6

h = 33.23 m

Thus, at 33.23 m the speed will be 12 m/s

6 0

3 years ago