No it isn't. (Unless you connect it backwards.)
If the primary has 10 turns and the secondary has 70 turns,
then the voltage that appears across the secondary is
7 times the voltage that you feed to the primary.
If you're 'exciting' the primary with 170 volts, then you need
to be cautious around the secondary terminals, because there's
1,190 volts there !
If you want to use your transformer in a step-down configuration,
you can certainly connect it up the other way around.
Feed the 170 volts to the winding with 70 turns. You've reversed
the labels 'primary' and 'secondary', and that's OK. The voltage
at the terminals of the 10-turn winding will be (170/7) = 24.3 volts.
Answer:
Height, H = 25.04 meters
Explanation:
Initially the ball is at rest, u = 0
Time taken to fall to the ground, t = 2.261 s
Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

Here, a = g
H = 25.04 meters
So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.
Potential energy is the greatest when the the kinetic energy is the least. This occurs when the ball loses the energy to fly higher, and begins to fall back to the ground.
Explanation:
Given that,
Vector a = 4i+3j
Vector b = -13i+7j
We need to find the magnitude and direction of (a+b). So,
(a+b) = (4i+3j) + (-13i+7j)
= (4i-13i)+(3j+7j)
= -9i+10j
Magnitude of (a+b).

Direction of (a+b),

Hence, this is the required solution.
Answer:
Q = 59565 [J]
Explanation:
In order to calculate the amount of thermal energy needed we must use the following equation.

where:
m = mass = 150 [g]
Cp = 4.18 [J/g*°C]
Tfinal = 5 [°C]
Tinitial = 100 [°C]
Now replacing:
![Q=150*4.18*(100-5)\\Q=59565[J]](https://tex.z-dn.net/?f=Q%3D150%2A4.18%2A%28100-5%29%5C%5CQ%3D59565%5BJ%5D)