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Vadim26 [7]
3 years ago
9

If the force of the explosion was focused onto a smaller _____ of the window, then the pressure of the explosion on the window w

ould be even greater.
length
area
volume
density
Physics
2 answers:
ICE Princess25 [194]3 years ago
8 0
The answer is area
This is because pressure is the amount of pressure applied to the surface of an object per unit of area
Vaselesa [24]3 years ago
8 0

<u>Answer:</u> The correct answer is Area.

<u>Explanation:</u>

Pressure exerted on an object is defined as the ratio of force applied to the surface area.

Mathematically,

p=\frac{F}{a}

Where, p = pressure

F = force applied

a = surface area

From the above relation, pressure is inversely related to area. As, the pressure increases, the area will be small and vice-versa.

So, when force of the explosion was focused on a smaller area, then the the pressure of the explosion on the window was greater.

Hence, the correct answer is Area.

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Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly
loris [4]

Answer: 36.86\°

Explanation:

According to the described situation we have the following data:

Horizontal distance between lily pads: d=2.4 m

Ferdinand's initial velocity: V_{o}=5 m/s

Time it takes a jump: t=0.6 s

We need to find the angle \theta at which Ferdinand jumps.

In order to do this, we first have to find the <u>horizontal component (or x-component)</u> of this initial velocity. Since we are dealing with parabolic movement, where velocity has x-component and y-component, and in this case we will choose the x-component to find the angle:

V_{x}=\frac{d}{t} (1)

V_{x}=\frac{2.4 m}{0.6 s} (2)

V_{x}=4 m/s (3)

On the other hand, the x-component of the velocity is expressed as:

V_{x}=V_{o}cos\theta (4)

Substituting (3) in (4):

4 m/s=5 m/s cos\theta (5)

Clearing \theta:

\theta=cos^{-1} (\frac{4 m/s}{5 m/s})

\theta=36.86\° This is the angle at which Ferdinand the frog jumps between lily pads

4 0
3 years ago
A Cathode of initial mass 10.00g weigh to 10.05g
Leto [7]

Answer:

i'm sorry i'm not a physics student

6 0
3 years ago
How long( in hours, will it take for 500 000 C of charge to flow through a diode if it requires
Alina [70]

Answer:

277.78 hours

Explanation:

The formula for calculating the amount of charge is expressed as;

Q = It

I is the current

t is the time

Given

I =0.05A

Q = 50,000C

Required

Time t

Recall that: Q = It

t = Q/I

t = 50,000/0.05

t = 1,000,000secs

Convert to hours

1,000,000secs  = 1,000,000/3600

1,000,000secs = 277.78 hours

Hence it will take 277.78 hours for the charge to flow through the diode

6 0
3 years ago
Why in a rollercoaster the height of the tracks is either equal to or less than the first track
umka2103 [35]

Answer:

I really don't know

Explanation:

sorry

6 0
2 years ago
Calculate the heat flux (in W/m^2) through a sheet of a metal 14 mm thick if the temperatures at the two faces are 350 and 140°C
ExtremeBDS [4]

Answer:

Explanation:

The rate of conductive heat transfer in watts is:

q = (k/s) A ΔT

where k is the heat conductivity, s is the thickness, A is the area, and ΔT is the temperature difference.

a)

Given k = 52.4 W/m/K, s = 0.014 m, and ΔT = 350-140 = 210 K, we can find q/A:

q/A = (52.4 / 0.014) (210)

q/A = 786,000 W/m²

b)

Given that A = 0.42 m², we can find q:

q = (0.42 m²) (786,000 W/m²)

q = 330,120 W

A watt is a Joule per second.  Convert to Joules per hour:

q = 330,120 J/s * 3600 s/hr

q = 1.19×10⁹ J/hr

c)

If we change k to 1.8 W/m/K:

q = (k/s) A ΔT

q = (1.8 / 0.014) (0.42) (210)

q = 11,340 J/s

q = 4.08×10⁷ J/hr

d)

If k is 52.4 W/m/K and s is 0.024 m:

q = (k/s) A ΔT

q = (52.4 / 0.024) (0.42) (210)

q = 192,570 J/s

q = 6.93×10⁸ J/hr

5 0
2 years ago
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