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Vadim26 [7]
3 years ago
9

If the force of the explosion was focused onto a smaller _____ of the window, then the pressure of the explosion on the window w

ould be even greater.
length
area
volume
density
Physics
2 answers:
ICE Princess25 [194]3 years ago
8 0
The answer is area
This is because pressure is the amount of pressure applied to the surface of an object per unit of area
Vaselesa [24]3 years ago
8 0

<u>Answer:</u> The correct answer is Area.

<u>Explanation:</u>

Pressure exerted on an object is defined as the ratio of force applied to the surface area.

Mathematically,

p=\frac{F}{a}

Where, p = pressure

F = force applied

a = surface area

From the above relation, pressure is inversely related to area. As, the pressure increases, the area will be small and vice-versa.

So, when force of the explosion was focused on a smaller area, then the the pressure of the explosion on the window was greater.

Hence, the correct answer is Area.

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A 97.1 kg horizontal circular platform rotates freely with no friction about its center at an initial angular velocity of 1.63 r
sammy [17]

Answer:

the final angular velocity of the platform with its load is 1.0356 rad/s

Explanation:

Given that;

mass of circular platform m = 97.1 kg

Initial angular velocity of platform ω₀ = 1.63 rad/s

mass of banana m_{b} = 8.97 kg

at distance r = 4/5  { radius of platform }

mass of monkey m_{m} = 22.1 kg

at edge = R

R = 1.73 m

now since there is No external Torque

Angular momentum will be conserved, so;

mR²/2 × ω₀ = [ mR²/2 + m_{b} (\frac{4}{5} R)² + m_{m}R² ]w

m/2 × ω₀ = [ m/2 + m_{b} (\frac{4}{5} )² + m_{m} ]w

we substitute

w = 97.1/2 × 1.63 / ( 97.1/2 + 8.97(16/25) + 22.1

w = 48.55 × [ 1.63 / ( 48.55 + 5.7408 + 22.1 )

w = 48.55 × [ 1.63 / ( 76.3908 ) ]

w = 48.55 × 0.02133

w = 1.0356 rad/s

Therefore; the final angular velocity of the platform with its load is 1.0356 rad/s

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