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Vadim26 [7]
3 years ago
9

If the force of the explosion was focused onto a smaller _____ of the window, then the pressure of the explosion on the window w

ould be even greater.
length
area
volume
density
Physics
2 answers:
ICE Princess25 [194]3 years ago
8 0
The answer is area
This is because pressure is the amount of pressure applied to the surface of an object per unit of area
Vaselesa [24]3 years ago
8 0

<u>Answer:</u> The correct answer is Area.

<u>Explanation:</u>

Pressure exerted on an object is defined as the ratio of force applied to the surface area.

Mathematically,

p=\frac{F}{a}

Where, p = pressure

F = force applied

a = surface area

From the above relation, pressure is inversely related to area. As, the pressure increases, the area will be small and vice-versa.

So, when force of the explosion was focused on a smaller area, then the the pressure of the explosion on the window was greater.

Hence, the correct answer is Area.

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A stuntman with a mass of 80.5 kg swings across a moat from a rope that is 11.5 m. At the bottom of the swing the stuntman's spe
goldenfox [79]

Answer:

  • No
  • 5.49 m/s

Explanation:

The net force required to accelerate the stuntman in a circular arc of radius 11.5 m will be ...

  F = mv²/r . . . . where this m is the mass being accelerated, v is the tangential velocity, and r is the radius.

Here, the net force needs to be ...

  F = (80.5 kg)(8.45 m/s)²/(11.5 m) . . . . . where this m is meters

  ≈ 499.8175 kg·m/s² = 499.8 N

Gravity exerts a force on the stuntman of ...

  F = mg = (80.5 kg)(9.8 m/s²) = 788.9 kg·m/s² = 788.9 N

Then the tension required in the rope/vine is ...

  499.8 N+788.9 N= 1288.7 N

This is more than the capacity of the rope, so we do not expect the stuntman to make it across the moat.

_____

The allowed net force for centripetal acceleration is ...

  1000 N -788.9 N = 211.1 N

Then the allowed velocity is ...

  211.1 = 80.5v²/11.5

  30.16 = v² . . . .  multiply by 11.5/80.5

  5.49 = v . . . . . . take the square root

The maximum speed the stuntman can have is 5.49 m/s.

_____

<em>Comment on crossing the moat</em>

The kinetic energy at the bottom of the swing translates to potential energy at the end of the swing. At the lower speed, the stuntman cannot rise as high, so will traverse a shorter arc. At 8.45 m/s, the moat could be about 16.8 m wide; at 5.49 m/s, it can only be about 11.5 m wide.

5 0
3 years ago
How does lifting electromagnet working​
dmitriy555 [2]

Explanation:

Large electrical shifting magnets have concentrated retaining strength to lift dense, ferric objects and a deep-reaching magnetization. An immensely useful materials management technique is these electromagnetic rises.

3 0
2 years ago
What does Newton's first law describe?
ahrayia [7]
B I think. Newtons first law talks about how if some thing is traveling at like 5 mph it’ll stay at 5 mph forever until the force is put on it.
7 0
3 years ago
This speed is measured with respect to the space station the spacecraft was originally launched from. In interstellar space the
valentinak56 [21]

Answer:

15193.62 m/s

Explanation:

t = Time taken = 6.5 hours

u = Initial velocity = 0 (Assumed)

m = Mass of rocket = 1380 kg

F = Thrust force = 896 N

v = Final velocity

a = Acceleration of the rocket

Force

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{896}{1380}\\\Rightarrow a=0.6493\ m/s^2

Equation of motion

v=u+at\\\Rightarrow v=0+0.6493\times 6.5\times 60\times 60\\\Rightarrow v=15193.62\ m/s

The velocity of the rocket after 6.5 hours of thrust is 15193.62 m/s

5 0
3 years ago
Danny is riding his bike at 12m/s he tries to pop a wheelie but he fails hits a curb flies through the air and comes to a comple
maxonik [38]

Answer:

a = -0.4m/s²

Explanation:

v_f = v_I + (a)(t)

a(t) = v_f-v_I

a = (v_f-v_I)/t

a = (0m/s-12m/s)/30s

a = -0.4m/s²

8 0
2 years ago
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