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nordsb [41]
3 years ago
14

Water drips from a shower head (the sprayer at the top of the shower) and falls onto the floor 2.4 m below. The droplets are fal

ling at regular intervals (equal amounts of time between drops), with the first drop hitting the floor at the instant that the fourth drop starts to fall.When the first drop hits the floor (as the fourth drop is dripping from the shower head), how far below the shower head is the third drop?
Physics
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

The third drop is 0.26m

Explanation:

The drop 1 impacts at time T is given by:

T=sqrt(2h/g)

T= sqrt[(2×2.4)/9.8]

T= sqrt(4.8/9.8)

T= sqrt(0.4898)

T= 0.70seconds

4th drops starts at dT=0.70/3= 0.23seconds

The interval between the drops is 0.23seconds

Third drop will fall at t= 0.23

h=1/2gt^2

h= 1/2×9.81×(0.23)^2

h= 0.26m

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Determine the gain in the potential energy when a 8.0 kg box is raised 17.2 m.
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<h2>The answer is 1376 J</h2>

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8. An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object? _______________
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Answer:

Mass of object is 0.5kg

Explanation:

Given the following data;

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3 years ago
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