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nordsb [41]
2 years ago
14

Water drips from a shower head (the sprayer at the top of the shower) and falls onto the floor 2.4 m below. The droplets are fal

ling at regular intervals (equal amounts of time between drops), with the first drop hitting the floor at the instant that the fourth drop starts to fall.When the first drop hits the floor (as the fourth drop is dripping from the shower head), how far below the shower head is the third drop?
Physics
1 answer:
expeople1 [14]2 years ago
4 0

Answer:

The third drop is 0.26m

Explanation:

The drop 1 impacts at time T is given by:

T=sqrt(2h/g)

T= sqrt[(2×2.4)/9.8]

T= sqrt(4.8/9.8)

T= sqrt(0.4898)

T= 0.70seconds

4th drops starts at dT=0.70/3= 0.23seconds

The interval between the drops is 0.23seconds

Third drop will fall at t= 0.23

h=1/2gt^2

h= 1/2×9.81×(0.23)^2

h= 0.26m

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Answer:

Friction force is 0.1375 N

Solution:

As per the question:

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Integrating the above eqn:

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From eqn (1) and (2):

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Thus the Frictional force is given by:

F = \frac{1}{2}\times 5.5\times 1.25\times 0.04 = 0.1375\ N

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3 years ago
A block of mass 5 kg slides down an inclined plane that has an angle of 10. If the inclined plane has no friction and the block
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The kinetic energy of the block  when it reaches the bottom is 39.2 J.

<h3>Kinetic energy of the block at the bottom</h3>

Apply the principle of conservation of energy.

K.E(bottom) = P.E(top)

P.E(top) = mgh

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P.E(top) = 5 x 9.8 x 0.8

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Learn more about kinetic energy here: brainly.com/question/25959744

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1 year ago
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Answer:

120,000

Explanation:

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This question can be solved by using Pythagora's Theorem.

The resultant magnitude of the movement is "42.5 units".

The x and y components of the movement are given. We can use Pythagora's Theorem to find the resultant of these movements. Hence, applying the Pythagora's Theorem<em>:</em>

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