Answer:
0.074m/s
Explanation:
We need the formula for conservation of momentum in a collision, this equation is given by,

Where,
= mass of ball
= mass of the person
= Velocity of ball before collision
= Velocity of the person before collision
= velocity of ball afer collision
= velocity of the person after collision
We know that after the collision, as the person as the ball have both the same velocity, then,


Re-arrenge to find
,

Our values are,
= 0.425kg
= 12m/s
= 68.5kg
= 0m/s
Substituting,


<em />
<em>The speed of the person would be 0.074m/s after the collision between him/her and the ball</em>
Answer: 7750 J
Explanation:
Mechanical energy is potential energy added to kinetic energy.
5000 + 2750 J = 7750 J
For this specific problem, the photons have been localized to
D<span>x = </span>0.027m
uncertainty. I am hoping that this answer has satisfied your
query about and it will be able to help you, and if you’d like, feel free to
ask another question.
Answer:
Speed at which it will reach the ground is given as

Total time for which it will remain in air is given as
t = 6.3 s
Explanation:
As we know that the object is projected upwards with speed


now when it will reach the ground then we have

so we have


so we have

Now speed of the object when it reaches the ground is given as


