Answer:
<em>1.49 x </em>
<em></em>
<em></em>
Explanation:
Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>
Mathematically, this can be stated as
∝ 
<em>to remove the proportionality sign we introduce a constant</em>
= k
k = 
Where T is the orbital period,
and R is the orbit around the sun.
For mars,
T = 687 days
R = 2.279 x
for mars, constant k will be
k = 
= 3.987 x 
For Earth, orbital period T is 365 days, therefore
= 3.987 x x
= 3.34 x 
R =<em> 1.49 x </em><em></em>
<u>I have assumed a weight of 120 N on Earth.</u>
Answer:
<em>The object weighs 20 N on the moon</em>
Explanation:
Weight
The weight of an object depends on the mass m of the object and the acceleration of gravity g of the place they are in.
The formula to calculate the weight is:
W = m.g
If g_e is the acceleration of gravity on Earth, and g_m is the acceleration of gravity on the moon, we know:
Dividing by ge:
An object of weight We=120 N on planet Earth has a mass of:
Multiplying by gm:
Substituting the ratio of accelerations of gravity:
Since m.gm is the weight on the Moon Wm:
The object weighs 20 N on the moon
Answer:
<h2>98 J</h2>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 5 × 9.8 × 2
We have the final answer as
<h3>98 J</h3>
Hope this helps you
Question: calculate their densties in Si unit.
200mg,0.0004m³
Answer:
0.5 kg/m³
Explanation:
Applying,
D = m/V........................ Equation 1
Where D = density, m = mass, V = volume.
From the question,
Given: m = 200 mg = (200/1000000) kg = 2.0×10⁻⁴ kg, V = 0.0004 m³ = 4.0×10⁻⁴ m³
Substitute these values into equation 1
D = (2.0×10⁻⁴ kg)/(4.0×10⁻⁴)
D = 2/4
D = 0.5 kg/m³
Hence the density in S.I unit is 0.5 kg/m³
may vary depending on the organization.
