highest energy level to the ground state.
Explanation:
The transition from the highest energy level to the ground state.
An electron has a discrete amount of energy accrued to it in any energy level it belongs to.
Electrons can transition between one energy level or the other.
- When electrons change state, they either release or absorb energy.
- When an atom absorbs energy, they move from their ground to final state which is consistent with the energy of the final state.
- When electrons release energy, they move from excited state to their ground state.
- Electrons will release the greatest amount of energy when they move from the highest energy level to the ground state.
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Voltage, resistance and current are the three components that must be present for a circuit to exist. A circuit will not be able to function without these three components. Voltage is the main electrical source that is present in a circuit. :)
Answer:
L= 2 mH
Explanation:
Given that
Frequency , f= 10 kHz
Maximum current ,I = 0.1 A
Maximum energy stored ,E= 1 x 10⁻⁵ J
The maximum energy stored in the inductor is given as follows

Where ,L= Inductance
I=Current
E=Energy
Now by putting the values in the above equation


L=0.002 H
L= 2 mH
We know that frequency f is given as

C=Capacitance , f=frequency ,L=Inductance
Now by putting the values






Therefore the inductance and capacitance will be 2 mH and 1.26 x 10⁻⁷ F respectively.
Answer:
Resonance depends on objects, this may happen for example when you play guitar in a given room, you may find that for some notes the walls or some object vibrate more than for others. This is because those notes are near the frequency of resonance of the walls.
So waves involved are waves that can move or affect objects (in this case the pressure waves of the sound, and the waves that are moving the wall).
this means that the waves are mechanic waves.
Now, in electromagnetics, you also can find resonance frequencies for electromagnetic waves trapped in things called cavities, but this is a different topic.
The product of (wavelength) times (frequency) is always the same number ...
the speed of the wave in whatever material it's traveling through. So if the
frequency is increased, then the wavelength must <em><u>de</u></em>crease by the same
factor, in order to keep the product the same.