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777dan777 [17]
3 years ago
13

1.A wave has a period of 20 seconds. What is the frequency?

Physics
1 answer:
Vesnalui [34]3 years ago
6 0

1).  Frequency = (1/period) = 1/(20sec)  =  (1/20) per sec  .

2).  Frequency= (3 waves) / (4 sec) = (3/4) (per sec)
       Period  =  (1/freq)  =  1/(3/4 per sec) = (4/3) sec

3). Speed= (freq) x (wavelength)  (2 per sec) x (5 m)  =  (2 x 5) ( m per sec)
     Speed doesn't depend on amplitude.


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)If a force of 5.00 N is needed to open a 90.0 cm wide door when applied at the edge opposite the hinges, what force must be app
masha68 [24]

Answer:

A force of 12.857 newtons must be applied to open the door.

Explanation:

In this case, a force is exerted on the door, a moment is performed and the door is opened. If moment remains constant, the force is inversely proportional to distance respect to axis of rotation passing through hinges. That is:

F \propto \frac{1}{r}

F = \frac{k}{r} (Eq. 1)

Where:

F - Force, measured in newtons.

k - Proportionality ratio, measured in newton-meters.

r - Distance respect to axis of rotation passing through hinges, measured in meters.

From (Eq. 1) we get the following relationship and clear the final force within:

F_{A}\cdot r_{A} = F_{B}\cdot r_{B}

F_{B}=\left(\frac{r_{A}}{r_{B}} \right)\cdot F_{A}(Eq. 2)

Where:

F_{A}, F_{B} - Initial and final forces, measured in newtons.

r_{A}, r_{B} - Initial and final distances, measured in meters.

If we know that F_{A} = 5\,N, r_{A} = 0.9\,m and r_{B} = 0.35\,m, then final force is:

F_{B}= \left(\frac{0.9\,m}{0.35\,m} \right)\cdot (5\,N)

F_{B} = 12.857\,N

A force of 12.857 newtons must be applied to open the door.

3 0
3 years ago
Followed by the previous question: presume that the electron performs a uniform circular motion around the hydrogen nucleus. Wha
Ksivusya [100]

Answer:

A_c=87.73*10^{21}m/s

Explanation:

From the question we are told that

r=5\times 10^{-11}

T=1.5 \times 10^{-16}

Generally the equation for velocity is mathematically given as

Velocity (v)=\frac{2 \pi r}{t}

V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}

V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}

Generally the equation for Centripetal acceleration is mathematically given as

A_c=\frac{V^2}{r}

A_c=(\frac{20.944*10^5)}{r5*10^{-11}}

A_c=87.73*10^{21}m/s

8 0
2 years ago
Two forces,one of 12 N and another of 24 N,act on a body in such a way that they make an angle of 90degree with each other.Find
jok3333 [9.3K]

Answer:

26.83 N.

Explanation:

If the angle between two vector is 90°, to get the resultant, we use Pythagoras theorem.

a² = b²+c²......................... Equation 1

Where a = R = Resultant, b =  12 N, c = 24 N.

Substitute these values into equation 1

R² = 12²+24²

R² = 144+576

R² = 720

√R² = √720

R = 26.83 N.

Hence, the result of the two force is 26.83 N.

4 0
3 years ago
Kellie found a sample of a pure element. She carefully studied the sample and made a list of its properties.
aivan3 [116]
1. (C.) -Si- is silicone which at room temp is a solid and it's a hard crystalline Brittle rock basically...

2. And it will Be D. NOT C... i can't stand user's who throw out answers for free points.... 
3 0
3 years ago
A 25 kg mass is accelerated by a force at a rate of 5 m/s2. What is the magnitude of the force that accelerates the man?
svlad2 [7]
Force=mass*acceleration
F=ma
F=25*5
F=100 N
8 0
3 years ago
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