Question

A train traveling at 6.4 m/s accelerates at 0.10 m/s 2 over a distance of 100 m. How large is the train’s final velocity?

Answer 1

The final velocity of the train at the end of the given distance is 7.81 m/s.

The given parameters;

• initial velocity of the train, u = 6.4 m/s
• acceleration of the train, a = 0.1 m/s²
• distance traveled, s = 100 m

The final velocity of the train at the end of the given distance is calculated using the following kinematic equation;

v² = u² + 2as

v² = (6.4)² + (2 x 0.1 x 100)

v² = 60.96

v = √60.96

v = 7.81 m/s

Thus, the final velocity of the train at the end of the given distance is 7.81 m/s.

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