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Oksanka [162]
3 years ago
7

The Sun's surface temperature is closest to _____.

Physics
2 answers:
alina1380 [7]3 years ago
8 0

Answer:

6000 K

Explanation:

The Sun's surface temperature is about 6000 K. It was estimated by obtaining its spectrum. The peak wavelength obtained from the spectrum indicates the surface temperature. The Wein's Displacement Law states that the surface temperature is inversely proportional to the wavelength.

T_{sun}=6000 K

garik1379 [7]3 years ago
5 0
The answer is b because the sun's surface temperature is 5,778 K.
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What wavelength would a ripple in water have if the frequency is 1.8 Hz and a
Yuki888 [10]

Explanation:

825m/s / 1.8Hz = 458.33m

6 0
2 years ago
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A scientist spends most of her time observing the motion of objects and how they behave. Which branch of science is she most lik
olga55 [171]
The scientist is likely to be studying kinematics.
Kinematics is the branch of science, specifically physics, which is concerned with the motion of objects without reference to the forces that induce this motion. An example of kinematics is studying the change in velocity of an object over time or the distance covered by an object in a specified amount of time.
7 0
2 years ago
The force between a pair of charges is 900 newtons. The distance between the charges is 0.01 meters. If one of the charges is 2e
Maksim231197 [3]

Answer:

\fbox{strength  \: of \:  the \:  other \:  charge  =  - 0.0196 Ke \: Coulomb}

Explanation:

Given:

Force between pair of charges= 900 newtons

The distance between the charges = 0.01 meters

Strength of Charge first q1 = 2e-10 Coulomb

To find:

Strength of Charge second q2 = ____ Coulomb?

Solution:

We know that,

Force between two charges separate by distance r is given by the equation,

|F| =  K_e \frac{q1 \cdot \: q2}{ {r}^{2} }  \\ 900 =K_e  \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times  {10}^{ - 4}  =  K_e {(2e - 10)\cdot \: q2} \\ q2 =   \frac{9 \times  {10}^{ - 2} }{(2e - 10) K_e}  \\  \\  \fbox{We \:  know \:  that \:  e = 2.71 } \\  substituting \: the \: value \: \\ q2 =  \frac{9 \times  {10}^{ - 2} }{(2 \times 2.71 - 10)K_e}  \\ q2 =  \frac{0.09}{ - 4.58 K_e}  \\ q2 =  \frac{-0.0196}{K_e}\: coulomb

\fbox{strength  \: of \:  the \:  other \:  charge  =  - 0.0196 Ke \: Coulomb}

<em><u>Thanks for joining brainly community!</u></em>

3 0
2 years ago
A single slit 1.4 mmmm wide is illuminated by 460-nmnm light. Part A What is the width of the central maximum (in cmcm ) in the
mamaluj [8]

Answer:

<h2> 1.643*10⁻⁴cm</h2>

Explanation:

In a single slit experiment, the distance on a screen from the centre point is expressed as y = \frac{\delta m \lambda d}{a} where;

\delta m is the first two diffraction minima = 1

\lambda is light wavelength

d is the distance of diffraction pattern from the screen

a is the width of the slit

Given \lambda = 460-nm = 460*10⁻⁹m

d = 5.0mm = 5*10⁻³m

a = 1.4mm = 1.4*10⁻³m

Substituting this values into the formula above to get width of the central maximum y;

y = 1*460*10⁻⁹ * 5*10⁻³/1.4*10⁻³

y = 2300*10⁻¹²/1.4*10⁻³

y = 1642.86*10⁻⁹

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Converting the final value to cm,

since 100cm = 1m

x = 1.643*10⁻⁶m

x = 1.643*10⁻⁶ * 100

x = 1.643*10⁻⁴cm

Hence, the width of the central maximum in the diffraction pattern on a screen 5.0 mm away is  1.643*10⁻⁴cm

3 0
3 years ago
1. If the strength of the magnetic field at A is 16 units, the strength of the magnetic field at B is _____.
Alchen [17]

1. The strength of magnetic field at A is 64 unit, then the magnetic field strength at B. is 256 units.

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2. If the strength of magnetic field B is 6 units then the strength magnetic field at A is 24 units.

which is 256 : 4 = 16 units.

Magnetic field is one of the two ways where the intensity of magnetic field is being expressed.

8 0
3 years ago
Read 2 more answers
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