Answer:
A = $10,441.68
A = P + I where
P (principal) = $10,400.00
I (interest) = $41.68
Step-by-step explanation:
First, convert R as a percent to r as a decimal
r = R/100
r = 0.02/100
r = 0.0002 rate per year,
Then solve the equation for A
A = P(1 + r/n)nt
A = 10,400.00(1 + 0.0002/2)(2)(20)
A = 10,400.00(1 + 0.0001)(40)
A = $10,441.68
Summary:
The total amount accrued, principal plus interest, with compound interest on a principal of $10,400.00 at a rate of 0.02% per year compounded 2 times per year over 20 years is $10,441.68.
Answer:
B = 4
T = 2
Step-by-step explanation:
First, figure out the equation.
We know that bicycles have 2 wheels, that there are 3 on a tricycle, and there are a total of 14 wheels and a total of 6 bicycles and tricycles.
Let b stand for bicycles and t stand for tricycles:
14 = 2b + 3t
6 = b + t
We can figure out the amount of either by rearranging the second equation to isolate one variable. I will solve it in two ways
In the first way, I will solve for b
(-t) 6 = b + t (-t)
6 - t = b
Plug this into the first equation and solve for remaining variable
14 = 2(6 - t) +3t
14 = 12 - 2t + 3t
14 = 12 +t
-12 -12
2 = t
6 - 2 = b
b = 4
The second way was to solve for t first
(-b) 6 = b + t (-b)
6 - b = t
14 = 2b + 3(6 - b)
14 = 2b + 18 - 3b
(-18) 14 = 18 -b (-18)
-4/-1 = -b/-1
b = 4
6 - 4 = t
t = 2
It doesn't matter which way you go, they both give you the exact same answer.
Sooo, recap!
1) write equations
2) switch the easier of the two to isolate one variable
3) substitute to find other variable (x2)
4) Find answers! =D
Hope this helps!
Answer:
30.18
Step-by-step explanation:
Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
Answer:
First one
Step-by-step explanation:
