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rewona [7]
3 years ago
11

6. The temperature of a mass of tin increases from 24.0 degrees C to 34.0 degrees C when 250 J of thermal energy are added. Calc

ulate the mass of the tin. The theoretical specific heat capacity of tin is 0.228 J/g degrees C.
Physics
1 answer:
irina [24]3 years ago
6 0

Answer:

110 g

Explanation:

q = mCΔT

where q is heat, m is mass, C is specific heat capacity, and ΔT is change in temperature.

Given q = 250 J, C = 0.228 J/g/°C, and ΔT = 10.0 °C:

250 J = m (0.228 J/g/°C) (10.0 °C)

m = 110 g

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Ice has a specific heat of 2.093Jg ∘C, liquid water's specific heat is 4.184Jg ∘C, and steam has a specific heat of 1.864Jg ∘C.
Ivan

Answer:

The liquid phase will have the lowest temperature change upon heating.

Explanation:

Assuming no phase change due to heating, we know that the temperature change, is proportional to the mass heated, being the proportionality constant  a quantity that depends on the material, and represents the resistance of the material to change the temperature, called specific heat.

So, if we assume that the mass is the same for the three phases, and that the amount of heat supplied is also the same,the phase with the highest specific heat will have the lowest temperature change.

So, the liquid phase will be the one that exhibits this behavior, as the specific heat of liquid water (4.184 J/gºC) is the highest among the three phases.

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Daring Darless wishes to cross the Grand Canyon of the Snake River by being shot from a cannon. She wishes to be launched at 65
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Answer:

She must be launched with minimum speed of <u>57.67 m/s</u> to clear the 520 m gap.

Step-by-step explanation:

Given:

The angle of projection of the projectile is, \theta =65°

Range of the projectile is, R=520 m.

Acceleration due to gravity, g=9.8\ m/s^2

The minimum speed to cross the gap is the initial speed of the projectile and can be determined using the formula for range of projectile.

The range of projectile is given as:

R=\frac{v_{0}^2\sin2\theta}{g}

Plug in all the given values and solve for minimum speed, v_0.

520=\frac{v_{0}^2\sin(2(65))}{9.8}\\520\times 9.8=v_{0}^2\sin(130)\\5096=1.532v_{0}^2\\v_0^2=\frac{5096}{1.532}\\v_0^2=3326.371\\v_0=\sqrt{3326.371}=57.67\textrm{ m/s}

Therefore, she must be launched with minimum speed of 57.67 m/s to clear the 520 m gap.

3 0
4 years ago
If the force on the tympanic membrane (eardrum) increases by about 1.4 N above the force from the atmospheric pressure, the memb
Sveta_85 [38]

Answer:

10.58 ft

Explanation:

Force, F = 1.4 N

Diameter of membrane = 7.4 mm

radius of membrane, r = 7.4 / 2 = 3.7 mm = 3.7 x 10^-3 m

Area, A = 3.14 x (3.7 x 10^-3)^2 = 4.3 x 10^-5 m^2

Density, d = 1.03 x 10^3 kg/m^3

Pressure at depth, P = h x d x g

Let h be the depth.

Pressure = force / Area

h x 1.03 x 10^3 x 9.8 = 1.4 / (4.3 x 10^-5)

h = 3.225 m = 10.58 ft

Thus, the depth of water is 10.58 ft.

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The objective lens in a DVD player must move quickly to keep the laser beam focused on the disc's reflective layer. Why must thi
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Explanation:

The small mass of lens in a DVD player accounts for small inertia of the lens. Hence, even on application of force of small magnitude, the lens is rapidly accelerated. Moreover, the small mass of lens also accounts for lower resistance to change in its motion and therefore, again can be rapidly accelerated back and forth.

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