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Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J
Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.
<h3>What is gravitational potential energy?</h3>- The energy possessed by a body by virtue of its position in gravitational field of earth is called gravitational potential energy.
- The gravitational potential energy of a body at a height h with respect to the height h will be,
- Expression for gravitational potential energy loss will be,
- The total energy before the ball dropped will be,
- The total energy after when the ball rebounds to 1.5m will be,
- The total energy loss will be,
Thus, we can conclude that, the energy loss will be,0.294J.
Learn more about the gravitational potential energy here:
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Answer:
distance travelled by the block is 0.796 m
{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }
Explanation:
Given that;
mass of block m = 0.200 kg
distance travelled d = 0.796 m
time t = 2.00 s
m₂ = 0.400 kg
If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?
Now, using the second equation of motion;
d = ut + ( × at²)
as the object started from rest, u=0
so, we substitute
0.796 = 0×2 + ( × a(2)²)
0.796 = 0 + ( × 4a)
0.796 = 2a
a = 0.796 / 2
a = 0.398 m/s²
using first equation of motion
= u + at
we substitute
= 0 + 0.398 × 2
= 0.796 m/s
now, average velocity is given as;
= ( 0.796 m/s + 0 ) / 2
= ( 0.796 m/s + 0 ) / 2
now, distance as the block moves in 2s will be;
D = [( 0.796 m/s + 0 ) / 2 ] × 2
D = 0.796 m
Therefore, distance travelled by the block is 0.796 m
{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }