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4 years ago

He amount of current flowing in a circuit can be measured by

1 answer:

7 0

First question:
The magnitude of current flowing in a circuit is described in
units of Amperes. The device used to measure it is an Ampmeter,
or Ammeter.

Second question:
This question is so absurd that it should not be dignified with an
answer. Although 'E' is often used as the symbol for Electromotive
force, potential difference, and voltage, there's certainly no rule.
Anyone is free to use 'M', 'Q', 'Θ', or 'Щ' to denote voltage when
they write electrical formulas, just as long as they make sure to
explain the meaning of whatever symbols they use.

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A ____ is one of the tiny dots of light that form a grid on your screen.

Degger [83]

Hi there

The answer is pixel

Hope this helps

8 0

3 years ago

Read 2 more answers

If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he

forsale [732]

The amount of heat needed to increase the temperature of a substance by $\Delta T$ is given by
$Q= mC_s \Delta T$
where m is the mass of the substance, Cs is its specific heat capacity and $\Delta T$ is the increase of temperature.

If we re-arrange the formula, we get
$C_s = \frac{Q}{m \Delta T}$
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
$C_s = \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C$

6 0

3 years ago

Read 2 more answers

How much heat is removed from 60 grams of steam at 100 °C to change it to 60 grams

Harrizon [31]

Answer:

45200J

Explanation:

Given parameters:

Heat of vaporization of water = 2260J/g

Mass of steam = 20g

Temperature = 100°C

Unknown:

Energy released during the condensation = ?

Solution:

This change is a phase change and there is no change in temperature

To find the amount of heat released;

H = mL

m is the mass

L is the latent heat of vaporization

Insert the parameters and solve;

H = 20g x 2260J/g

H = 45200J

4 0

2 years ago

a 1210 kg roller coaster car is moving 6.33 m/s. as it approaches the station, brakes slow it down to 2.38 m/s over a distance o

Stels [109]

Answer:

4960 N

Explanation:

First, find the acceleration.

Given:

v₀ = 6.33 m/s

v = 2.38 m/s

Δx = 4.20 m

Find: a

v² = v₀² + 2aΔx

(2.38 m/s)² = (6.33 m/s)² + 2a (4.20 m)

a = -4.10 m/s²

Next, find the force.

F = ma

F = (1210 kg) (-4.10 m/s²)

F = -4960 N

The magnitude of the force is 4960 N.

4 0

3 years ago

Read 2 more answers

A circular loop of flexible iron wire has an initial circumference of 165.0cm, but its circumference is decreasing at a constant

vovangra [49]

Answer:

emf induced in the loop, at the instant when 9.0s have passed = 1.576 * 10 ⁻² V.

Direction is counter clockwise.

Explanation:

See attached pictures.

6 0

3 years ago