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labwork [276]
3 years ago
5

The mass of an object is

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer: The mass of an object is a measure of the object's inertial property, or the amount of matter it contains. Hope this is what your looking for.

Explanation:

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Does a negative exponent mean that the number is less than 1 yes or no​
Masja [62]

Answer:

When a number is written in scientific notation, the exponent tells you if the term is a large or a small number. A positive exponent indicates a large number and a negative exponent indicates a small number that is between 0 and 1.

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if a solution measured with the miscalibrated meter (above) gave a reading of 6.50 at 20oC, what should be the true pH (give 2 d
Andreas93 [3]

Answer:

Explanation:

Ph is the major of acidity or basicity of a solution. On a scale of 0 to 14

PH = -log 10 ^(H+)

Therefore PH= -log 10^(6.5) =0.81

Therefore PH of the solution is 0.81

This solution is therefore an acidic solution

7 0
4 years ago
What is crystal field splitting?
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3 years ago
Which shows an isomer of the molecule below?
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B

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3 0
3 years ago
Read 2 more answers
A 25.0-mL sample of 0.150 M hydrazoic acid, HN3, is titrated with a 0.150 M NaOH solution. What is the pH after 13.3 mL of base
tamaranim1 [39]

Answer:

pH ≅ 4.80

Explanation:

Given that:

the volume of HN₃ = 25 mL = 0.025 L

Molarity of HN₃ = 0.150 M

number of moles of HN₃ = 0.025 × 0.150

number of moles of HN₃ =  0.00375  mol

Molarity of NaOH = 0.150 M

the volume of NaOH = 13.3 mL = 0.0133

number of moles of NaOH = 0.0133× 0.150

number of moles of NaOH = 0.001995 mol

The chemical equation for the reaction of this process can be written as:

HN_3 + OH- ---> N^-_{3} + H_2O

1 mole of hydrazoic acid react with 1 mole of hydroxide to give nitride ion and water

thus the new number of moles of HN₃ = 0.00375 - 0.001995 = 0.001755 mol

Total volume used in the reaction =  0.025 +  0.0133 = 0.0383  L

Concentration of HN_3 = \dfrac{0.001755}{0.0383} = 0.0458 M

Concentration of N^{-}_3 = \dfrac{ 0.001995 }{0.0383} = 0.0521 M

GIven that :

Ka = 1.9 x 10^{-5}

Thus; it's pKa = 4.72

pH =4.72 +  log(\dfrac{ \ 0.0521}{0.0458})

pH =4.72 + log(1.1376)

pH =4.72 + 0.05598

pH =4.77598

pH ≅ 4.80

3 0
3 years ago
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