The ratios which are needed to determine the mass of oxygen produced from the decomposition of 10 grams of potassium chlorate are;
- 31.998 g O2 : 1 mole O2
- 3 mole O2 : 2 mole KClO3
- 112.55 g KClO31 mole KClO3
From stoichiometry;
- We can conclude that according to the reaction;
3 moles of oxygen requires 2 moles of KClO3 to be produced.
And from molar mass analysis;
- 31.998 g O2 is equivalent to 1 mole O2
- O2112.55 g KClO3 is equivalent to 1 mole KClO3
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Answer:
240 N/m
Explanation:
Using the formula as follows:
U = ½kx²
Where;
U = elastic potential energy (J)
K = spring constant (N/m)
x = stretched displacement (m)
According to the information provided in this question,
U = 35J
x = 0.54m
k = ?
U = ½kx²
35 = ½ × k × 0.54²
35 = ½ × k × 0.2916
35 = 0.2916k/2
70 = 0.2916k
k = 70 ÷ 0.2916
k = 240.05
To 2s.f, the spring constant (k) = 240 N/m.
Answer: Adding a reactant will shift the reaction towards the products.
Adding a product will shift the reaction towards the reactants.
Removing a reactant will shift the reaction towards the reactants.
Removing a product will shift the reaction towards the products.
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
Adding a reactant will increase the concentration of reactants and hence the reaction will try to undo the increase by shifting the reaction towards the products.
Adding a product will increase the concentration of products and hence the reaction will try to undo the increase by shifting the reaction towards the reactants.
Removing a reactant will decrease the concentration of reactants and hence the reaction will try to undo the decrease by shifting the reaction towards the reactants.
Removing a product will decrease the concentration of products and hence the reaction will try to undo the decrease by shifting the reaction towards the products.
Answer:
b) U235 & U238
Explanation:
Isotopes are the variants of a element which differ in the number of neutrons , and in the nucleon number consequently . All isotopes of the element have same number of the protons but different numbers of the neutrons.
(a) Isotopes are the properties of an element. Hence, not isotopes.
(b) Uranium is the element which exists in mass number 235 and 238 and they are the isotopes of the uranium element. Hence, they are isotopes.
(c) They represent same specie. Hence, not isotopes.
(d) Isotopes are the properties of an element. Hence, not isotopes.
