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just olya [345]

3 years ago

9

Celery stalks that are immersed in fresh water for several hours become stiff and hard. similar stalks left in asalt solution be

come limp and soft. from this we can deduce that the cells of the celery stalks are

1 answer:

galina1969 [7]3 years ago

4 0

Plasmolysed because of osmosis as the salt solution has lower water potential than the cells of the stalk

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Which mixture can be separated based on differences in the particle size of the components?

Rina8888 [55]

Answer: Mixtures you can separate are like cereal and milk. Hope that helps

Explanation: Filteration is required to separate a mixture.

So heterogeneous mixures (that contain substances with different particle sizes) can be separated with a filter.

Homogeneous mixtures are uniform in composition so they will not be able to be separated.

5 0

4 years ago

(a) In a gaseous sample of oxygen atoms and diatomic oxygen in equilibrium at 298K andunder a pressure of 1atm, what fraction of

ZanzabumX [31]

Answer:

Explanation:see below as shown from pics

7 0

3 years ago

As temperature increases, the amount of solute that a solvent can dissolve increases. True False

ra1l [238]

<span>As temperature increases, the amount of solute that a solvent can dissolve increases.</span>

<span>Answer: False
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6 0

3 years ago

PLEASE HELP ASAP ESSAY WORTH 15 POINTS! ONLY GENIUS!

Sliva [168]

Answer:

According to the law of conservation of mass, the mass of reactants will be equal to the mass of the products.

Explanation:

5 0

3 years ago

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

$n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC$

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

$n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH$

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

$m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO$

4. Compute the moles of oxygen by using its molar mass:

$n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO$

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

$C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1$

6. Search for the closest whole number (in this case multiply by 2):

$C_3H_6O_2$

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

$M=12*3+1*6+16*2=74g/mol$

Which is about three times in the molecular formula, for that reason, the actual formula is:

$C_9H_{18}O_6$

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0

3 years ago