Answer:
number of moles of water (n) = 1.383 x10 ⁻⁵ mol
Explanation:
Data Given:
No. of molecules of water = 8.33×10¹⁸
No. of Mole of water = ?
Formula Used to calculate
no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number
Avogadro's no. = 6.023 x10²³
So the formula could be written as
no. of moles (n) = no. of molecules of water /6.023 x10²³
Put the values in above formula
no. of moles (n) = 8.33×10¹⁸ /6.023 x10²³
no. of moles (n) = 8.33×10¹⁸ /6.023 x10²³
no. of moles (n) = 1.383 x10 ⁻⁵
so 1.383 x10 ⁻⁵ moles of water are represented by 8.33×10¹⁸ molecules of water.
Here are some trends you should know.
Electronegativity increases as you go right and up along the periodic table.
So, (1) is wrong
Atomic mass increases as you go right and down along the periodic table.
So, (2) is wrong
Proton number or atomic number increases as you go right and down in the table.
So, (3) is correct
Metallic character increases as you go left and down along the periodic table.
So, (4) is wrong
Answer:
A. Able to be lost or gained in chemical reactions.
Explanation:
Only electrons are lost or gained.
Answer:
247 ml
Explanation:
How many mL of 0.150 M HF solution are required to produce 0.0370 moles of HF 0.150 moles/ liter = 0.150/1000 moles/ml =0.000150 moles/ml
0.000150 x ? = 0.0370 moles HF
? = 0.0370/0.000150 = 247 ml
check
247 ml = 247/1000 L = 0.247
(0.247) x (0.150) =0.370 check
