All categories

3 years ago

ILL MARK BRAINIEST WHOEVER ANSWERS CORRECTLY

Chemistry

1 answer:

natulia [17]3 years ago

4 0

Answer:

I think its A

sorry if im wrong

Explanation:

You might be interested in

How many atoms of lead are in 3.25 moles of lead

musickatia [10]

Answer: 1.96x10^24 atoms

Explanation:

3.25*6.02214076*10^23 atoms = 1.96x10^24

6 0

3 years ago

When 2.0 mol of methanol is dissolved in 45 grams of water, what is the mole fraction of methanol

kaheart [24]

The mole fraction of methanol in the mixture is 0.444

We'll begin by calculating the number of mole of water.

Mass of water = 45 g

Molar mass of water = 18 g/mol

Mole of water =?

Mole = mass / molar mass

Mole of water = 45 / 18

Mole of water = 2.5 moles

Finally, we shall determine the mole fraction of methanol.

Mole of water = 2.5 moles

Mole of methanol = 2 moles

Total mole = 2 + 2.5 = 4.5 moles

Mole fraction of methanol =?

Mole fraction = mole / total mole

Mole fraction of methanol = 2 / 4.5

Mole fraction of methanol = 0.444

Thus, the mole fraction of methanol is 0.444

Learn more about mole fraction:

brainly.com/question/15444997

7 0

3 years ago

Crude oil is a mixture of many liquids. The crude oil enters the bottom of a tall column, where the mixture is heated. The subst

Yanka [14]

Boiling point ..................................................

7 0

3 years ago

Read 2 more answers

All organisms have the same number of cells<br>A. true<br>B. false

MakcuM [25]

B. false is the answer of this question

4 0

3 years ago

Read 2 more answers

Carbon-14 is a radioactive isotope that decays according to first-order kinetics in a process that has a half-life of 5730 years

Sliva [168]

Answer : The time passed in years is $2.83\times 10^3\text{ years}$

Explanation :

Half-life = 5730 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{5730\text{ years}}$

$k=1.21\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the time passed.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $1.21\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = ?

a = let initial amount of the reactant = X g

a - x = amount left after decay process = $71\% \times (x)=\frac{71}{100}\times (X)=0.71Xg$

Now put all the given values in above equation, we get

$t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{X}{0.71X}$

$t=2831.00\text{ years}=2.83\times 10^3\text{ years}$

Therefore, the time passed in years is $2.83\times 10^3\text{ years}$

8 0

3 years ago