2 years ago

ILL MARK BRAINIEST WHOEVER ANSWERS CORRECTLY

Chemistry

1 answer:

natulia [17]2 years ago

4 0

Answer:

I think its A

sorry if im wrong

Explanation:

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Answer:

0.1388 g

Explanation:

The mass of $BaSO_4$ obtained on precipitation = 236 mg

1 mg = 0.001 g

Thus, Mass of $BaSO_4$ = 0.236 g

Molar mass of $BaSO_4$ = 233.43 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{0.236\ g}{233.43\ g/mol}$

Moles of $BaSO_4$ = 0.001011 moles

According to the reaction,

$Ba^{2+}+SO_4{2-}\rightarrow BaSO_4$

Thus, moles of barium = 0.001011 moles

Molar mass of barium = 137.327 g/mol

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Answer:

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