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3 years ago

How many grams of ferric oxide will you need to make 1.5 M solution?

Chemistry

1 answer:

Masteriza [31]3 years ago

3 0

Answer:Stoichiometry calculations are about calculating the amounts of substances that react and form in a

chemical reaction. For example, based on the balanced chemical equation, we can calculate the

amount of a product substance that will form if we begin with a specific amount of one or more

reactants. Or, you may have a target amount of product to prepare. How much starting compounds

are needed to prepare this amount? These are practical calculations that are done frequently by

chemists.

The Method

For practically all stoichiometry problems, we want to use the. . . .

Fabulous Four Steps

Step 1: Write the balanced chemical equation for the reaction.

Step 2: Calculate the moles of "given" substance. If more than one reactant amount is given,

calculate the moles of each to determine which is the limiting reactant.

Step 3: Calculate the moles of "desired" substance from your answer in Step 2 using the

coefficients from the balanced chemical equation. If more than one reactant was given originally, you

can calculate the moles of product twice, based on the moles of each reactant. The reactant that

gives the smaller moles of product is the limiting reactant. Keep this answer for Step 4.

Step 4: Convert your answer in Step 3 to the units the problem asks for. Usually this is grams,

but it could be volume (for gases or liquid solutions) or concentration (such as molarity, for solutions).

Again in brief:

1. Balanced reaction

2. Moles of "given" substance(s)

3. Moles of "desired" substance such as a product

4. Convert Step 3 answer to the units asked fo

Explanation:

You might be interested in

Calculate the freezing point and boiling point of a solution containing 8.15 g of ethylene glycol (C2H6O2) in 96.3 mL of ethanol

pishuonlain [190]

Answer: The freezing point of solution is -117.54°C and the boiling point of solution is 80.48°C

Explanation:

To calculate the mass of ethanol, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of ethanol = 0.789 g/mL

Volume of ethanol = 96.3 mL

Putting values in above equation, we get:

$0.789g/mL=\frac{\text{Mass of ethanol}}{96.3mL}\\\\\text{Mass of ethanol}=(0.789g/mL\times 96.3mL)=75.98g$

Calculating the freezing point:

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

$\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}$

To calculate the depression in freezing point, we use the equation:

$\Delta T_f=iK_fm$

Or,

$\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

where,

Freezing point of pure solution = -114.1 °C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_f$ = molal freezing point elevation constant = 1.99°C/m

$m_{solute}$ = Given mass of solute (ethylene glycol) = 8.15 g

$M_{solute}$ = Molar mass of solute (ethylene glycol) = 62 g/mol

$W_{solvent}$ = Mass of solvent (ethanol) = 75.98 g

Putting values in above equation, we get:

$-114.1-\text{Freezing point of solution}=1\times 1.99^oC/m\times \frac{8.15\times 1000}{62g/mol\times 75.98}\\\\\text{Freezing point of solution}=-117.54^oC$

Hence, the freezing point of solution is -117.54°C

Calculating the boiling point:

Elevation in boiling point is defined as the difference in the boiling point of solution and freezing point of pure solution.

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

where,

Boiling point of pure solution = 78.4°C

i = Vant hoff factor = 1 (For non-electrolytes)

$K_b$ = molal boiling point elevation constant = 1.20°C/m.g

$m_{solute}$ = Given mass of solute (ethylene glycol) = 8.15 g

$M_{solute}$ = Molar mass of solute (ethylene glycol) = 62 g/mol

$W_{solvent}$ = Mass of solvent (ethanol) = 75.98 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-78.4=1\times 1.20^oC/m\times \frac{8.15\times 1000}{62\times 75.98}\\\\\text{Boiling point of solution}=80.48^oC$

Hence, the boiling point of solution is 80.48°C

3 0

4 years ago

Which subatomic particle is not found at the center of the atom?

Snezhnost [94]

The answer is nucleus

8 0

4 years ago

Read 2 more answers

Would you expect hydrogen chloride to be a gas, a liquid or a solid, at room temperature and pressure? Explain your answer

Vlada [557]

At room temperature hydrogen chloride is a colorless gas with a sharp or pungent odor. Under pressure or at temperatures below –85°C (-121°F), it is a clear liquid.

6 0

3 years ago

CHEM PLZ HELP

marusya05 [52]

Answer:

Increase in CO2 (g) over time.

No NaHCO3 (s) will be left after a time

Explanation:

The reaction, shown below;

2NaHCO3(s) → Na2CO3(s)+CO2(g)+H2O(ℓ) is a decomposition reaction. A decomposition reaction is a kind of chemical reaction in which a given chemical specie breaks up to give other chemical species. Decomposition may be induced by heat or light.

Usually, there is only one reactant in a decomposition reaction; the specie that disintegrates into the products. This reactant usually decreases in concentration steadily because it is converted into products. This is why the mass of NaHCO3(s) in the system continues to decrease steadily until it finally falls to zero.

Conversely, the concentration (for aqueous) or volume (for gases) or mass (for solid) products of the reaction increases steadily as the reaction progresses. This explains why the volume of CO2 in the system will steadily increase over time.

7 0

3 years ago

Writing Prompt/Open-Ended Question

tino4ka555 [31]

Answer:

If you are given a chemical equation and specific amounts for each reactant in grams, you have to follow these steps, in order, to determine how much product can possilby be made:

1. Convert each reactant into moles of the product.

2. Determine which reactant is the limiting reactant.

3. Convert the moles of product, from the limiting reactant, to grams.

Explanation:

8 0

3 years ago