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DaniilM [7]
3 years ago
13

Andre drew a quadrilateral with four right angles and two pairs of congruent sides. What type of quadrilateral did he draw? Expl

ain your answer.
Type of Quadrilateral:______________
EXPLAIN WHY IT IS THAT QUADRILATERAL!​

Mathematics
1 answer:
Kaylis [27]3 years ago
6 0

Answer:

The type of quadrilateral is a rectangle

Step-by-step explanation:

we know that

A rectangle is a quadrilateral with four right angles and two pairs of congruent and parallel sides

see the attached  figure to better understand the problem

m

AB=CD

BC=AD

therefore

The type of quadrilateral is a rectangle

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The question is a little hard to understand... let me see what i can do. I'll edit what i figure out on here. :) (PS) Did you reword the question? Do you think you could double check and make sure this is what the question looks like?


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Answer:

a=-3/7 b=-2/8 c=-0.2

Step-by-step explanation:

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5 0
3 years ago
Given that A=27, B=43 and c=17, solve triangle ABC to the nearest hundredth
katrin2010 [14]
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] / <span> <span> <span> 1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) = <span> <span> <span> 0.96374829001368
Angle A = 15.475

Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span> <span> <span> <span> 154.85

</span></span></span>Finally, calculating the third angle is quite easy
Angle C =  180 - Angle (A) - Angle(B)
Angle C =  180 - 15.475 - 154.85
Angle C =  9.675

Source:
http://www.1728.org/trigtut2.htm


6 0
3 years ago
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