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DaniilM [7]
3 years ago
13

Andre drew a quadrilateral with four right angles and two pairs of congruent sides. What type of quadrilateral did he draw? Expl

ain your answer.
Type of Quadrilateral:______________
EXPLAIN WHY IT IS THAT QUADRILATERAL!​

Mathematics
1 answer:
Kaylis [27]3 years ago
6 0

Answer:

The type of quadrilateral is a rectangle

Step-by-step explanation:

we know that

A rectangle is a quadrilateral with four right angles and two pairs of congruent and parallel sides

see the attached  figure to better understand the problem

m

AB=CD

BC=AD

therefore

The type of quadrilateral is a rectangle

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Jessie is saving up for a purse that is $890. She gets $8 allowance per week, and already has $80 saved up. How long will it tak
LekaFEV [45]

Answer:

101.25 weeks

Step-by-step explanation:

890-80=810

810/8=101.25

8 0
3 years ago
A student repeatedly measures the mass of an object using a mechanical balance and gets the following values: 560 g, 562 g, 556
MrRissso [65]

Answer: 2.76 g

Step-by-step explanation:

The formula to find the standard deviation:-

\sigma=\sqrt{\dfrac{\sum(x_i-\overline{x})^2}{n}}

The given data values : 560 g, 562 g, 556 g, 558 g, 560 g, 556 g, 559 g, 561 g, 565 g, 563 g.

Then,  \overline{x}=\dfrac{\sum_{i=1}^{10} x_i}{n}\\\\\Rightarrow\ \overline{x}=\dfrac{560+562+556+558+560+556+559+561+565+563}{10}\\\\\Rightarrow\ \overline{x}=\dfrac{5600}{10}=560

Now, \sum_{i=1}^{10}(x_i-\overline{x})^2=0^2+2^2+(-4)^2+(-2)^2+0^2+(-4)^2+(-1)^2+1^2+5^2+3^2\\\\\Rightarrow\ \sum_{i=1}^{10}(x_i-\overline{x})^2=76

Then, \sigma=\sqrt{\dfrac{76}{10}}=\sqrt{7.6}=2.76

Hence, the  standard deviation of his measurements = 2.76 g

6 0
3 years ago
Which value is a solution of the equation 2-8x=-6 ? ( 1point )
OleMash [197]
<span>Here the given equation is : 2-8x= -6 By bring -6 on the Left Hand size and taking 8x on the Right Hand side, the equation become. 2+6= 8X 8= 8X X=8/8 X=1 Hence value of X is 1. Hence correct option is A.</span>
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Help plssssssss number 1
olga nikolaevna [1]

Answer:

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Step-by-step explanation:

8 0
3 years ago
the sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger
Reil [10]
<h2>Answer:</h2>

x\geq 3 \ and \ x+1 \geq 4

<h2>Step-by-step explanation:</h2>

The question in this problem is:

<em>The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger. What are the numbers?</em>

<em />

First of all, let's name the first variable x which is the smaller number. Accordingly, the lager number will be x+1 given that those numbers are consecutive. On the other hand<em> at most </em>conveys the idea of an inequality, which is:

\leq \\ which \ means \ less \ than

So:

1. The sum of 2 consecutive integers can be written as:

v+(v+1)

2. Nine times the smaller and 5 times the larger can be written as:

9v-5(v+1)

Finally, the whole statement:

The sum of 2 consecutive integers is at most the difference between nine times the smaller and 5 times the larger:

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\

x+(x+1) \leq 9x-5(x+1) \\ \\ x+x+1\leq 9x-5x-5 \\ \\ 2x+1 \leq 4x-5 \\ \\ 6 \leq 2x \\ \\ \frac{6}{2} \leq \frac{2x}{2} \\ \\ 3 \leq x \\ \\ x\geq 3 \\ \\ and \\ \\ x+1 \geq 4

The two numbers are:

x\geq 3 \ and \ x+1 \geq 4

6 0
3 years ago
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