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2 years ago

10

If the speed of an object is tripled, its kinetic energy will be

2 answers:

Savatey [412]2 years ago

7 0

Answer:

if the speed of the object triples the kinetic energy becomes nine times the initial kinetic energy. If the speed of an object changes by a factor k, the change in the kinetic energy is of a factor k^2.

Explanation:

UkoKoshka [18]2 years ago

5 0

Answer:

it will be tripled bc it is going tripled the speed so the kinetic energy will be to hope this help

Explanation:

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PLEASE HELP, LOOK AT PHOTO PLZ!!!

PIT_PIT [208]

Answer:

a) 17 km

b) 9 km

Explanation:

The distance is the length of the path.

A to C: 5 km

B to C: 4 km

C to B: 4 km

B to C: 4 km

Total distance = 5 km + 4 km + 4 km + 4 km = 17 km

Displacement is the difference between the starting point and ending point.

Displacement = 9 km − 0 km = 9 km

3 0

3 years ago

How do modern scientists describe the make up of matter

mojhsa [17]

<span>Matter is considered by modern scientists to be anything in the universe that takes up mass. It can be in any state including solid, liquid, or gas. It can also hold potential and or kinetic energy.</span>

4 0

3 years ago

What is the wave length if the distance from the central bright region to the sixth dark fringe is 1.9 cm . Answer in units of n

Yuri [45]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The wavelength is $\lambda = 622 nm$

Explanation:

From the question we are told that

The distance of the slit to the screen is $D = 5 \ m$

The order of the fringe is m = 6

The distance between the slit is $d = 0.9 \ mm = 0.9 *10^{-3} \ m$

The fringe distance is $Y = 1.9 \ cm = 0.019 \ m$

Generally the for a dark fringe the fringe distance is mathematically represented as

$Y = \frac{[2m - 1 ] * \lambda * D }{2d}$

=> $\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}$

substituting values

=> $\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}$

=> $\lambda = 6.22 *10^{-7} \ m$

$\lambda = 622 nm$

8 0

2 years ago

Write the correct abbreviation for each metric unit

Romashka-Z-Leto [24]

Meter - m
Kilometer - km
Hectometer- hm
Dekameter - dam
Decimeter - dm
Centimeter - cm
Millimeter - mm
Micrometer - μm

5 0

2 years ago

A 0.290 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 30.0 pC charge on it

mojhsa [17]

Answer:

Therefore,

The potential (in V) near its surface is 186.13 Volt.

Explanation:

Given:

Diameter of sphere,

d= 0.29 cm

$radius=\dfrac{d}{2}=\dfrac{0.29}{2}=0.145\ cm$

$r = 0.145\ cm = 0.145\times 10^{-2}\ m$

Charge ,

$Q = 30.0\ pC=30\times 10^{-12}$

To Find:

Electric potential , V = ?

Solution:

Electric Potential at point surface is given as,

$V=\dfrac{1}{4\pi\epsilon_{0}}\times \dfrac{Q}{r}$

Where,

V= Electric potential,

ε0 = permeability free space = 8.85 × 10–12 F/m

Q = Charge

r = Radius

Substituting the values we get

$V=\dfrac{1}{4\times 3.14\times 8.85\times 10^{-12}}\times \dfrac{30\times 10^{-12}}{0.145\times 10^{-2}}$

$V=\dfrac{30}{16.117\times 10^{-2}}=186.13\ Volt$

Therefore,

The potential (in V) near its surface is 186.13 Volt.

3 0

3 years ago