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Mashutka [201]
2 years ago
12

8. A rectangle is measured to be 6.4 +0.2 cm by 8.3 $0.2 cm.

Physics
1 answer:
mamaluj [8]2 years ago
5 0

Answer:

a) The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty in its perimeter is 0.8 centimeters.

Explanation:

a) From Geometry we remember that the perimeter of the rectangle (p), measured in centimeters, is represented by the following formula:

p = 2\cdot (w+l) (1)

Where:

w - Width, measured in centimeters.

l - Length, measured in centimeters.

If we know that w = 6.4\,cm and l = 8.3\,cm, then the perimeter of the rectangle is:

p = 2\cdot (6.4\,cm+8.3\,cm)

p = 29.4\,cm

The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty of the perimeter (\Delta p), measured in centimeters, is estimated by differences. That is:

\Delta p = 2\cdot (\Delta w + \Delta l)  (2)

Where:

\Delta w - Uncertainty in width, measured in centimeters.

\Delta l - Uncertainty in length, measured in centimeters.

If we know that \Delta w = 0.2\,cm and \Delta l = 0.2\,cm, then the uncertainty in perimeter is:

\Delta p = 2\cdot (0.2\,cm+0.2\,cm)

\Delta p = 0.8\,cm

The uncertainty in its perimeter is 0.8 centimeters.

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A shot-putter accelerates a 7.5 kg shot from rest to 12 m/s .
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From the calculations, the power developed is 337.5 W.

<h3>What is the power developed?</h3>

First we must obtain the acceleration from;

v = u + at

u = 0 m/s because the motion started rom rest

v = at

a = v/t

a = 12 m/s/ 1.6 s

a= 7.5 m/s^2

The force is obtained from;

F = ma = 7.5 kg * 7.5 m/s^2 = 56.25 N

Now the distance covered is obtained from';

v^2 = u^2 + 2as

v^2 = 2as

s = v^2/2a

s = (12)^2/2 *  7.5

s = 9.6 m

Now;

Work = Fs = 56.25 N *  9.6 m = 540 J

Power expended =  540 J/ 1.6 s = 337.5 W

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The handles of the tools like screwdrivers and pliers used by electricians for repair work usually have plastics or rubber cover
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Will a heavier bowling ball hit pins better than a lighter bsll
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A baseball is hit from a height of 4 feet above the ground with an initial velocity of 110 feet per second and at an angle of 35
mrs_skeptik [129]

Answer:

Part a)

h = 62.2 ft

Part b)

It will not able to cross the pole

Explanation:

As we know that ball is hit with speed of 110 ft/s at an angle of 35 degree

so here we will say

v_y = 110 sin35

v_x = 110 cos35

now at the maximum height the vertical velocity will become zero

so here we can use kinematics

v_f^2 - v_y^2 = 2 a h

here we have

a = -32 ft/s^2

v_f = 0

v_y = 63.1 ft/s

now we have

0 - 63.1^2 = 2(-32)h

h = 62.2 ft

Part b)

now the height of ball is related to the distance from point of projection is given as

y = xtan\theta - \frac{gx^2}{2v^2cos^2\theta}

now we know that

x = 375 ft

y = 375(tan35) - \frac{(32)(375^2)}{2(110^2)(cos35)^2}

y = 262.6 - 277.12 = -14.5 ft

since its coming negative so it will not able to cross the pole

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2 years ago
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