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Use equations of motion to find the velocity just before it hits the floor:
<span>Vf^2 = Vi^2 + 2gx </span>
<span>Final velocity = 4.42m/s </span>
<span>Impulse is change in momentum so: </span>
<span>m(Vf - Vi) = 0.05(0 - 4.42) </span>
<span>= - 0.221 kg.m/s
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Answer:
0.0018 V
Explanation:
According to the law of conservation of energy, the kinetic energy gained by the particle is equal to the electric potential energy lost:
where
is the mass of the particle
is the final speed of the particle
q = -2.7 C is the charge
is the potential difference between the two points
Solving for , we find
The particle has been accelerated by this potential difference: since it is a negative charge, it means that the particle has moved from a point at lower potential towards a point of higher potential.
So, since the initial point is A and the final point is B, the result is