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Hunter-Best [27]
3 years ago
8

An electron in a hydrogen atom is excited with electrical energy to an excited state with n = 2. The atom then emits a photon. W

hat is the value of n for the electron following the emission?
Chemistry
1 answer:
Delicious77 [7]3 years ago
3 0

Answer:

The correct answer is n = 1

Explanation:

The moment the photon is emitted, the electron transaction occurs from a higher main energy level to a lower main energy level. Considering that the only main energy level below n = 2 is n = 1, so this is the energy level the electron must transition when the photon is emitted.

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What is meant by the half-life of a radioactive substance
Shtirlitz [24]

Answer:

Explanation:

The half life of a radioactive atom is the time taken for half of the radioactive nuclei to disintegrate. The shorter the half life, the faster a radioactive nuclei decays.

Half life is often expressed as:

                               Half life = \frac{0.693}{λ}

Where λ is the decay constant.

3 0
3 years ago
A liquid mixture composed of 20% CH4, 30% C2H4, 35% C2H2, and 15% C2H20. What is the average molecular weight of the mixture? a)
blondinia [14]

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

We are given:

Mass percentage of CH_4 = 20 %

So, mole fraction of CH_4 = 0.2

Mass percentage of C_2H_4 = 30 %

So, mole fraction of C_2H_4 = 0.3

Mass percentage of C_2H_2 = 35 %

So, mole fraction of C_2H_2 = 0.35

Mass percentage of C_2H_2O = 15 %

So, mole fraction of C_2H_2O = 0.15

We know that:

Molar mass of CH_4 = 16 g/mol

Molar mass of C_2H_4 = 28 g/mol

Molar mass of C_2H_2 = 26 g/mol

Molar mass of C_2H_2O = 48 g/mol

To calculate the average molecular mass of the mixture, we use the equation:

\text{Average molecular weight of mixture}=\frac{_{i=1}^n\sum{\chi_im_i}}{n_i}

where,

\chi_i = mole fractions of i-th species

m_i = molar masses of i-th species

n_i = number of observations

Putting values in above equation:

\text{Average molecular weight}=\frac{(\chi_{CH_4}\times M_{CH_4})+(\chi_{C_2H_4}\times M_{C_2H_4})+(\chi_{C_2H_2}\times M_{C_2H_2})+(\chi_{C_2H_2O}\times M_{C_2H_2O})}{4}

\text{Average molecular weight of mixture}=\frac{(0.20\times 16)+(0.30\times 28)+(0.35\times 26)+(0.15\times 42)}{4}\\\\\text{Average molecular weight of mixture}=6.75

Hence, the correct answer is Option c.

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4 years ago
3 Feas) + 4H20lg) Foog(s) + 4H₂ (g)
Nonamiya [84]

Answer:

Do you have options of answers for this question

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Which of the following is not a major environmental concern associated with nuclear fission plants? A. running out of enriched u
Aleksandr-060686 [28]
<span>D. unsafe disposal of radioactive waste produced by a nuclear power plant</span>
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COMPARE: Identify three ways that a biologist’s research is similar to an astronomer’s.
dalvyx [7]
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