There are 48.72 g Fluorine ions
<h3>Further explanation
</h3>
Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements
In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison
%F in CaF₂ :
mass of Fluorine :
So mass Fluorine ions(2 ions F in CaF₂⇒Ca²⁺+2F⁻) :
I think the answer is C. Runoff hopefully this helps
The answer is C, good luck mate
Answer:
Explanation:
From the information given:
Step 1:
Determine the partial pressure of each gas at total Volume (V) = 4.0 L
So, using:
![Total pressure= P [N_2] + P[Ar] \ \\ \\ . \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = (0.525 + 1.7)Bar \\ \\ . \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = 2.225 \ Bar](https://tex.z-dn.net/?f=Total%20pressure%3D%20P%20%5BN_2%5D%20%2B%20P%5BAr%5D%20%5C%20%5C%5C%20%5C%5C%20.%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%3D%20%280.525%20%2B%201.7%29Bar%20%5C%5C%20%5C%5C%20.%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%3D%202.225%20%5C%20Bar)
Now, to determine the final pressure using different temperature; to also achieve this, we need to determine the initial moles of each gas.
According to Ideal gas Law.
For moles N₂:
For moles of Ar:
Finally;
The final pressure of the mixture is:
P = 2.217 atm
P ≅ 2.24 bar
