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snow_tiger [21]
3 years ago
8

What is 3+2-8+9+8+0-6-9+8

Mathematics
1 answer:
monitta3 years ago
8 0

Answer:

7

Step-by-step explanation:

First,

3+2=5

5-8=-3

-3+9=6

6+8=14

14+0=14

14-6=8

8-9=-1

-1+8=7

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Step-by-step explanation:

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6 0
3 years ago
SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR
Sedbober [7]
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2 years ago
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What is the midpoint of the segment shown below ?
Hoochie [10]
I'm pretty sure it would be d. you have to add the xs and ys and divide each by 2.
7 0
3 years ago
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A group of 6p people are renting a vacation house together the price of the rental is 3p to the 2nd power if they split the cost
Tanya [424]
So we just do
cost/number of people=cost per 1 person
so
(6p)/(3p^2)
remember that you can split it up and make ones
\frac{6p}{3p^{2}}=\frac{6}{3p} times \frac{p}{p}=\frac{2}{1p} times \frac{p}{p} times \frac{3}{3}=\frac{2}{1p}  times 1 times 1=2/p

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4 0
3 years ago
I need help with this ASAP and can you explain so i can understand?!
Elanso [62]

Answer:

Adult tickets sold =  225

Student Tickets sold =  375

Step-by-step explanation:

Let:

Adult tickets sold = x

Student Tickets sold = y

Total tickets sold = 600

So, we can write: x+y = 600

Total money collected = 3037.50

Cost of 1 Adult ticket = $6.00

Cost of one Student ticket = $4.50

So, we can write: 6x+4.5y=3037.50

Now, we get a system of equations, that if solved we can find values of x and y

Let:

x+y = 600--eq(1)\\6x+4.5y=3037.50--eq(2)

We can solve using substitution method.

Finding value of x from eq(1) and putting it in eq(2)

We\:have\\x+y=600\\x=600-y

Put in eq(2)

6x+4.5y=3037.50\\6(600-y)+4.5y=3037.50\\3600-6y+4.5y=3037.50\\-1.5y=3037.50-3600\\-1.5y=-562.5\\y=\frac{-562.5}{-1.5}\\y=375

So, we get value of y = 375

Now put value of y in eq(1) to find value of x

x+y=600\\Put\:y=375\\x+375=600\\x=600-375\\x=225

So, we get value of x = 225

The Tickets sold will be:

Adult tickets sold = x = 225

Student Tickets sold = y = 375

3 0
2 years ago
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