Answer:
K = 9.4 *10^5
The reaction favor product formation
Explanation:
Equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium. Also it is defined as the ratio of the product of concentration of products to the product of concentration of reactants each term raised to power equal their stochiometric coefficients.
so, for the reaction,
- 2H₂ ₍g₎ + S₂ ₍g₎ → 2H₂S ₍g₎
The equilibrium constant can be expressed as following:
![K_{eq}=\frac{[H_2S]^2}{H_2]^2\times [S_2]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BH_2S%5D%5E2%7D%7BH_2%5D%5E2%5Ctimes%20%5BS_2%5D%7D)
where concentration of reactants and products is expressed in molarity Molarity=(no of moles/ Volume L)
So,
[H₂] = (0.50 mol / 1 L) = 0.50 M
[S₂] = (0.02 mol / 1 L) = 0.020 M
[H₂S] = (68.5 mol / 1 L) = 68.5 M
∴ K_{eq}=\frac{[68.5]^2}{0.50]^2\times [0.020]}=9.4*10^5
As the value of K is greater than 1, the reaction favor product formation.
The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.
The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an
individual gas in a mixture and n is total moles of the gas mixture. We
know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in
total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate
the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole
fraction of gas Y (x) and the total pressure (P) to calculate the
partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =
2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =
1.6 atm.
Answer:
1677693.6000000000000000000000000000000
4.9 moles of salt are required to be added to 1 kg water to change the boiling temperature
by 5°C.
<h3>What is the moles of Salt required to change the temperature of water by 5°C?</h3>
Based on the given equation, the molality of the solution is calculated as follows:
- Molality = change in temperature/ Kb × I
Change in temperature = 5 °C
Kb = 0.51
i = 2
Molality = 5/0.51 × 2 = 4.9 molal
Also, Molality = moles/kg of water
Moles of salt = molality × kg of water
Moles of salt = 4.9 × 1 = 4.9 moles.
Therefore, 4.9 moles of salt are required to be added to 1 kg water to change the boiling temperature
by 5°C.
Learn more about molality at: brainly.com/question/9149034
#SPJ1
20 g is the answer to make it a saturated solution
