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3 years ago

An unknown solution has a pH of 2 . How would you classify this solution?

Chemistry

2 answers:

o-na [289]3 years ago

7 0

Answer is: B. acidic.

pH (potential of hydrogen) is a numeric scale used to specify the acidity or basicity of an aqueous solution:

When pH is less than seven (pH<7), solution is acidic.

When is equal seven (pH = 7), solution is neutral.

When pH is greater than seven (pH > 7), solution is basic.

For example, hydrochloric acid( HCl) is acidic, it ionizes in water solution and gives the hydrogen cations and chloride anions (Cl⁻):

HCl(aq) → Cl⁻(aq) + H⁺(aq).

marin [14]3 years ago

7 0

B. ACIDIC :) pH<7 is considered to be acidic

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(3.4 x 10^4) x (2.35 x 10^6)

bija089 [108]

Answer:79900000000

Explanation:

79900000000

8 0

3 years ago

Consider the chemical equation. 2H2 + O2 mc022-1.jpg 2H2O What is the percent yield of H2O if 87.0 g of H2O is produced by combi

ch4aika [34]

Answer:

88.50 %

The balance chemical equation is as follow,

2 H₂ + O₂ → 2 H₂O

Step 1: Find the limiting reactant;

According to eq.

4.032 g (2 mole) H₂ reacts with = 32 g (1 mole) of O₂

So,

11 g of H₂ will react with = X g of O₂

Solving for X,

X = (11 g × 32 g) ÷ 4.032 g

X = 87.301 g of O₂

Therefore, H₂ is the limiting reactant as O₂ is present in excess.

Step 2: Calculating %age Yield;

According to eq.

4.032 g (2 mole) H₂ produces = 36.032 g (1 mole) of H₂O

So,

11 g of H₂ will react with = X g of H₂O

Solving for X,

X = (11 g × 36.032 g) ÷ 4.032 g

X = 98.301 g of H₂O

So,

Actual Yield = 87 g

Theoretical Yield = 98.301 g

Using formula = Actual Yield / Theoretical Yield × 100

= 87 g / 98.301 × 100

= 88.50 %

4 0

3 years ago

Read 2 more answers

The products obtained from hydroboration-oxidation of cis-2-butene are identical to the products obtained from hydroboration-oxi

Rudik [331]

Answer:

a) Attached below

b) The presence of racemic mixture found as product in both cases shows that products are identical ( i.e. they have same configuration

Explanation:

Diagrams of the products obtained from hydroboration-oxidation of cis-2-butene , hydroboration-oxidation of trans-2-butene.

attached below

The presence of racemic mixture found as product in both cases shows that products are identical ( i.e. they have same configuration )

7 0

3 years ago

Write an equation that shows the reaction between acetic acid and triethylamine (CH3CH2)3N. Draw all non-bonding lone electron p

Anni [7]

Answer:

-) Acid-base reaction

-) Carboxylic acid, alcohol, alkene and ketone

Explanation:

For the reaction between acetic acid and triethylamine, we will have an acid-base reaction. Therefore a salt would be produced in this case an "ammonium quaternary salt". Also, we have to remember that on this reaction the acid is the acetic acid and the base is the triethylamine. See figure 1

For the second question, we have to check the structure of Prostaglandin E1 in which we have the functional groups:

1) Carboxylic acid

2) Alcohol

3) Alkene

4) Ketone

See figure 2.

I hope it helps!

8 0

3 years ago

An alkyne with the molecular formula C6H10 was treated with ozone followed by water to produce only one type of carboxylic acid.

likoan [24]

Answer:

The first step of this ozonolysis produces an acid anhydrous with on hydrolysis gives the same Carboxylic acid

Explanation:

Please find attached the reaction steps

6 0

2 years ago