Answer:
Height, h = 13.02 meters
Explanation:
It is given that,
Spring constant of the spring, k = 750 N/m
It is compressed by 35 cm relative to its unstained length, x = 35 cm = 0.35 m
Mass of the object, m = 0.36 kg
When the spring is released, the mass is launched vertically in the air. We need to find the height attained by the mass at this position. On applying the conservation of energy as :
Energy stored in the spring = change on potential energy
h = 13.02 meters
So, the mass will reach a height of 13.02 meters. Hence, this is the required solution.
Explanation:
The given data is as follows.
= 0, = 0, = 0
= 17.0 m, = 2.10 sec
As the force P is constant and the mass "m" of the tool is constant then it means that the acceleration "a" will also be constant.
Now,
=
17.0 = 2.205a
a =
Also, we know that
F =
m =
So, m =
= 1.66 kg
Since, the tool is subject to its weight W and is in free fall. Hence,
10.0 m =
g = 2.411
Hence, weight of tool in Newtonia is as follows.
W = mg
=
= 4.00 N
Hence, weight of the tool on Newtonia is 4.00 N.
And, weight of the tool on the Earth is as follows.
W =
= 23.62 N
Hence, weight of the tool on Earth is 23.62 N.
60 or 1 hour because 5 times 12 equals 60
Answer:
See Explanation
Explanation:
We know that;
P= IV
Where;
P = power
I= current
V = voltage
Here, we have a voltage of 220V
Hence, for maximum rate;
P= IV
I = P/V
P = 840 W
V= 220 V
I= 840 W/220 V
I= 3.8 A
V = IR
R = V/I
R = 220/3.8
R = 57.9 Ω
For minimum heating;
P= 360 W
V= 220 V
I = P/V
I = 360 W/220V
I= 1.6 A
V= IR
R = V/I
R = 220 V/1.6 A
R = 137.5 Ω
Answer:
2 m/s²
Explanation:
the equations of motion are
S= ut +½at²
v² = u²+ 2as
v = u + at
s = (u+v)/2 × t
From the parameters given
u = 0m/s this is because it starts from rest
Distance (s) = 9m
Time (t) = 3s
Based on this the first equation would be used
s = ut + ½at²
Input values
9 = 0×3 + ½ × a x 3²
9 = 0 + 9a/2
9 = 4.5a
Divide both sides by 4.5
a = 9 / 4.5 m/s²
a = 2 m/s²
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