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VikaD [51]
3 years ago
11

Arrange the following in order of increasing boiling point: RbF, CO2, CH3OH, CH3Br. Explain your reasoning.

Chemistry
1 answer:
Llana [10]3 years ago
3 0
<span>The following is the order from lowest boiling point to highest based on the types of forces these compounds have: CO2 CH3Br CH3OH RbF CO2 is a nonpolar molecular compound. The only intermolecular force present is a relatively weak dispersion force, because of the small molar mass. CO2 will have the lowest boiling point. ď‚· CH3Br is a polar molecule. Dispersion forces (present in all matter) and dipoleâ’dipole forces will be present. This compound has the next highest boiling point. ď‚· CH3OH is a polar molecule, which can form hydrogen bonds; these are especially strong dipole-dipole attractions. Dispersion forces and hydrogen bonding are present to give this substance the next highest boiling point. ď‚· RbF is an ionic compound. Ionâ’ion attractions are much stronger than any intermolecular force. RbF has the highest boiling point</span>
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