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djyliett [7]
3 years ago
12

What is the solution to the equation 2/3x+x = -1/3x+14?

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

Answer: x = -7/2 = -3.500

x = 2

Step-by-step explanation:

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Divide.<br> Write your answer in simplest form.<br> -6/7 divided by (-5/4) =?
yulyashka [42]

Answer:

\sf \dfrac{24}{35}

Step-by-step explanation:

Use KCF method for fraction division.

  • Keep the first fraction.
  • Change the division operation to multiplication.
  • Flip the second fraction.

\sf \dfrac{-6}{7} \div \dfrac{-5}{4}=\dfrac{-6}{7}*\dfrac{-4}{5}

               \sf =\dfrac{(-6)*(-4)}{7*5}\\\\=\dfrac{24}{35}

8 0
1 year ago
Read 2 more answers
he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 115 bpm. Find the minimum sample size
malfutka [58]

Answer:

97

Step-by-step explanation:

Given that:

Low = 43bpm

High = 115 bpm

Error = 3

α = 90%

To find the range estimate :

Standard destviation = (high - low) / 4

Standard deviation = (115 - 43) / 4

Standard deviation = 72/4 = 18

The sample size,(n) :

n = [(Zα/2 * sd)/E] ²

2 - tail = (Zα/2) = 1.645

[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²

= 97.41

Sample size = 97

5 0
3 years ago
Some animals on farms eat hay to get energy. A cow can eat 24 pounds of hay each day. Write and evaluate an expression to find h
vladimir1956 [14]

Answer:

7392 pounds

Step-by-step explanation:

22x24x14

multiplication my friend

7 0
3 years ago
What’s the error and how can I correct it number 24.
Aloiza [94]

The error is that 9 shouldnt be written as nine it should be written as 3x3 or 3^2. So the answer should be 2^3 x 3^2 because 9 can be divided into even more prime factors of 72.

4 0
3 years ago
Read 2 more answers
For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?
Nastasia [14]

Answer:

k=0 and k=3.

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of k that makes those coordinates equal.

k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0\\

Using the null factor property, we have

k=0\\k-3=0 \implies k=3

Therefore, the given relation is not a function when k=0 and k=3.

7 0
3 years ago
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