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Alex Ar [27]
3 years ago
6

How can you determine the number of protons in the nucleus of an atom of any of the elements listed in the table?

Chemistry
1 answer:
stealth61 [152]3 years ago
6 0
The number of protons is equal to the atomic number of every element in the periodic table.
Example: The atomic number of Niobium (Nb) is 41. Therefore, the number of protons is also 41.
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Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c
wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

5g/m³*1000=5000kg/m³

4 0
3 years ago
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For the following word equations, write it as a chemical equation, then balance it.
Lorico [155]

4K+O2-----------2K2O

7 0
3 years ago
Compared to winds on the earth the winds on Saturn are much stronger. <br><br> True or False?
Yanka [14]
This is most definitly true
3 0
3 years ago
In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to
labwork [276]

Answer : 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

Solution : Given,

Mass of NH_3 = 100 g

Molar mass of NH_3 = 27 g/mole

Molar mass of N_2 = 28 g/mole

First we have to calculate moles of NH_3.

\text{ Moles of }NH_3=\frac{\text{ Mass of }NH_3}{\text{ Molar mass of }NH_3}= \frac{100g}{27g/mole}=3.7moles

The given balanced chemical reaction is,

N_2(g)+3H_2(g)\rightarrow 2NH_3(g)

From the given reaction, we conclude that

2 moles of NH_3 produced from 1 mole of N_2

3.7 moles of NH_3 produced from \frac{1mole}{2mole}\times 3.7mole=1.85moles of N_2

Now we have to calculate the mass of N_2.

Mass of N_2 = Moles of N_2 × Molar mass of N_2

Mass of N_2 = 1.85 mole × 28 g/mole = 51.8 g

Therefore, 51.8 g of nitrogen are needed to produce 100 grams of ammonia gas.

5 0
3 years ago
Medical implants and high-quality jewelry items for body piercing are frequently known by a trade name, G23Ti, which means "surg
mrs_skeptik [129]

Answer:

Ti6Al4V1 or Ti6Al4V

Explanation:

So, from the question above we are given the following Important data or parameters or information which is going to help us in solving this question and they are;

The "surgical-grade" titanium is made up of 64.3% titanium, 24.19% aluminum and 11.42% vanadium.

This is a stoichiometry Question so in order to be able to solve this question one must have the basic knowledge of stoichiometry, it is advisable that one revise it.

So, let us delve right into the solution of this question. Recall that, the formula for Calculating the number of moles = mass/molar mass.

Hence, the number of moles of titanium,Ti = 64.3/47.87 = 3 moles.

Also, the number of moles of aluminum = 24.19/26.98 = 0.8966

For vanadium; 11.42/51 = 0.22

The next step is to divide each number of moles component by the lowest number of mole, that is;

Ti = 1.34/ 0.22 = 6; Al = 0.8966/0.22= 4 and V = 0.22/0.22 = 1.

Thus, the emperical formula is = Ti6Al4V.

7 0
3 years ago
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