Idk but here something that made my day
Answer:
1. a) 0,18
2. e) The reaction proceeds to the left, forming more BrCl(g).
Explanation:
1. In a gas reaction as:
2SO₂(g) +O₂(g) ⇄ 2SO₃(g)
it is possible to convert kp to kc using:
kp = kc (RT)^Δn
Where kp is gas equilibrium constant, kc is equilibrium constant (13), R is gas constant (0,082atmL/molK), T is temperature (900K), and Δn is number of moles of gas products - number of moles of gas reactants (That is 2 - (2+1) = -1). Replacing:
kp = 13×(0,082atmL/molK×900K)^-1
<em>kp = 0,18</em>
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2. Based on Le Chatelier's principle, the change in temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system. For the reaction:
2 BrCl(g) ⇄ Br₂(g) + Cl₂(g).
The addition of 0,050M of each compound cause <em>the reaction proceeds to the left, forming more BrCl(g)</em> because based on the reaction, you need two moles of BrCl per mole of Br₂(g) and Cl₂(g) to keep the system in the same. But you are adding the same proportion of moles of each compound.
I hope it helps!
When the enthalpy change of the reaction is positive the reaction is endothermic
this means that the reaction is absorbing energy from the surrounding to the vessel
<h3>Answer:</h3>
No, it wouldn't affect the volume.
<h3>Explanation:</h3>
Let us suppose the masses of metal object before and after shape change to be,
Mass before shape change = 2.5 g
Mass after shape change = 2.5 g
As the shape change has not affected on the mass so in both states it will remain 2.5 g.
Secondly, as density will remain same for both states because it is intensive property of a particular matter and is considered a characteristic property. Hence, it will also remain constant before and after shape change. Assume the density to be 2 g.mL⁻¹.
Therefore the volume calculated will be,
Before shape change:
Volume-1 = Density × Mass
Volume-1 = 2 g.mL⁻¹ × 2.5 g
Volume-1 = 5 mL
After shape change:
Volume-2 = Density × Mass
Volume-2 = 2 g.mL⁻¹ × 2.5 g
Volume-2 = 5 mL
<h3>Conclusion:</h3>
The volume is not affected by changing shape. Hence, after shape change the object will be having a volume of 5 mL.
