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Gekata [30.6K]
4 years ago
14

Listed below are possible solutes. In your possession is a beaker with 500 milliliters of water. You want to make an aqueous sol

ution with the highest concentration of solute possible. Which two solutes could you mix with the water to achieve this?
I. Ammonia

I I. Hexane

I I I. Hexanol

I V. Octane

Answers:
I & II

I & III

II & III

II & IV
Chemistry
2 answers:
slavikrds [6]4 years ago
8 0

Answer: I & III

Explanation:  Solutes are the substances which are minimum in quantity and which is required to dissolve in the solvent (which is larger in quantity) in order to make a solution.

In the asked question, it is given that the water is the solvent and from the given solutes we have to pick which would make an aqueous solution with the highest concentration of solute possible.

Thus the most appropriate answers could be the Ammonia and hexanol which can make the highest possible concentration of solute as ammonia is the gas which is highly soluble in water and hexanol is an alcohol which has an affinity for water. Thus the correct option is I & III

vichka [17]4 years ago
7 0

Answer:

the answer is B  I & III

Explanation:

i took the quiz

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BlackZzzverrR [31]
<h3>Answer:</h3>

1.47 × 10²¹ molecules OF₂

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
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<u>Stoichiometry</u>

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<h3>Explanation: </h3>

<u>Step 1: Define</u>

0.132 g OF₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of OF₂ - 16.00 + 2(19.00) = 54.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 0.132 \ g \ OF_2(\frac{1 \ mol \ OF_2}{54.00 \ g \ OF_2})(\frac{6.022 \cdot 10^{23} \ molecules \ OF_2}{1 \ mol \ OF_2})
  2. Divide/Multiply:                                                                                               \displaystyle 1.47204 \cdot 10^{21} \ molecules \ OF_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.47204 × 10²¹ molecules OF₂ ≈ 1.47 × 10²¹ molecules OF₂

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3 years ago
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Answer: The specific heat of the unknown metal is 0.897J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

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m= mass of substance = 86.8 g

c = specific heat capacity = ?

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Final temperature of the water = T_f

Change in temperature ,\Delta T=T_f-T_i=(64.7)^0C

Putting in the values, we get:

5040=86.8\times c\times 64.7^0C

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