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Gekata [30.6K]
4 years ago
14

Listed below are possible solutes. In your possession is a beaker with 500 milliliters of water. You want to make an aqueous sol

ution with the highest concentration of solute possible. Which two solutes could you mix with the water to achieve this?
I. Ammonia

I I. Hexane

I I I. Hexanol

I V. Octane

Answers:
I & II

I & III

II & III

II & IV
Chemistry
2 answers:
slavikrds [6]4 years ago
8 0

Answer: I & III

Explanation:  Solutes are the substances which are minimum in quantity and which is required to dissolve in the solvent (which is larger in quantity) in order to make a solution.

In the asked question, it is given that the water is the solvent and from the given solutes we have to pick which would make an aqueous solution with the highest concentration of solute possible.

Thus the most appropriate answers could be the Ammonia and hexanol which can make the highest possible concentration of solute as ammonia is the gas which is highly soluble in water and hexanol is an alcohol which has an affinity for water. Thus the correct option is I & III

vichka [17]4 years ago
7 0

Answer:

the answer is B  I & III

Explanation:

i took the quiz

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Which of the following is/are considered alcohols?
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Answer: THE ANSWER IS D

Explanation:

an alcohol is a hydrocarbon chain with an hydroxyl group (OH)

A, B, AND C ARE ALL ALCOHOLS, SO THE ANSWER IS D

6 0
3 years ago
The measurement 0.41006 gram, rounded to three significant figures, is expressed as
atroni [7]

Answer:

option B = 0.410 g

Explanation:

The given measurement have five significant figures 41006. this measurement can be rounded to three significant figures i.e, 0.410 g.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

3 0
4 years ago
Will a precipitate (ppt) form when 300. mL of 2.0 × 10 –5 M AgNO 3 are added to 200. mL of 2.5 × 10 –9 M NaI? Answer yes or no,
Vsevolod [243]

Answer:

A precipitate will form, AgI

Explanation:

When Ag⁺ and I⁻ ions are in an aqueous media, AgI(s), a precipitate, is produced or not based on its Ksp expression:

Ksp = 8.3x10⁻¹⁷ = [Ag⁺] [I⁻]

<em>Where the concentrations of the ions are the concentrations in equilibrium</em>

For actual concentrations of a solution, you can define Q, <em>reaction quotient, </em>as:

Q = [Ag⁺] [I⁻]

<em>If Q > Ksp, the ions will react producing BaCO₃, if not, no precipitate will form</em>.

Actual concentrations of Ag⁺ and I⁻ are:

[Ag⁺] = [AgNO₃] = 2.0x10⁻⁵ × (300mL / 500.0mL) = 1.2x10⁻⁵M

[I⁻] = [NaI] = 2.5x10⁻⁹ × (200mL / 500.0mL) = 1.0x10⁻⁹M

<em>500.0mL is the volume of the mixture of the solutions</em>

Replacing in Q expression:

Q = [Ag⁺] [I⁻]

Q = [1.2x10⁻⁵M] [1.0x10⁻⁹M]

Q = 1.2x10⁻¹⁴

As Q > Ksp

<h3>A precipitate will form, AgI</h3>

8 0
3 years ago
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Answer:

V=20.2m3

Explanation:

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Applying the ideal gas equation

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225.4×V = n×8.314×295.5

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8 0
3 years ago
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AysviL [449]

Explanation:

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The way to identify binary acids is to spot the hydrogen and the non metal.

7 0
3 years ago
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