<span>he density of a material is defined as its mass per
unit volume. In this example, each volume of water is different and
therefore has a specific and unique mass. The mass of water is expressed
in grams (g) or kilograms (kg), and the volume is measured in liters (L), cubic centimeters (cm 3), or milliliters (mL).</span>
The moles of each element found in a 5.00 g nickel coin is calculated as below
moles =mass/molar mass
calculate the mass of each element =% composition of element/100 x total mass of nickel
Mn = 9/100 x5 = 0.45g
Cu=56/100 x5= 2.8 g
Ag= 35/100x5= 1.75 g
moles of each element is therefore=
Mn = 0.45g/54.94 = 8.19 x10^-3 moles
Ag=1.75g/107.87 g/mol = 0.0162 moles
Cu = 2.8 g/63.5 g/mol=0.0441 moles
Liquids transports over distances.
Answer:
Hydroxide concentration of the sample is 1.3x10⁻⁶M
Explanation:
The equilibrium constant of water, Kw, is:
H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)
Kw is defined as:
Kw = 1.7x10⁻¹² = [H⁺] [OH⁻]
As the sample is of pure water, both H⁺ and OH⁻ ions have the same concentration because come from the same equilibrium, that is:
[H⁺] = [OH⁻]
We can write the Kw expression:
1.7x10⁻¹² = [OH⁻] [OH⁻]
1.7x10⁻¹² = [OH⁻]²
1.3x10⁻⁶M = [OH⁻]
<h3>Hydroxide concentration of the sample is 1.3x10⁻⁶M</h3>
