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nasty-shy [4]
3 years ago
8

The state of matter that consists of electrically charged particles

Physics
1 answer:
hjlf3 years ago
6 0
The state of matter that consists of electrically charged particles is Plasma.
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Acid it is i believe........
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Can someone help me with universal gravation ​
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States that particles are attracts with every other particle. wich force is directily proportional product of two masses and inversely proportional to the distance between the centers.
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A 0.72-m long string has a mass of 4.2 g. The string is under a tension of 84.1 N. What is the speed of a wave on this string?
frosja888 [35]

The speed of the wave in the string is 83.4 m/s

Explanation:

For a standing wave in a string, the speed of the wave is given by the equation:

v=\frac{1}{2L}\sqrt{\frac{T}{m/L}}

where

L is the length of the string

T is the tension in the string

m is the mass of the string

In this problem, we have:

L = 0.72 m

m = 4.2 g = 0.0042 kg

T = 84.1 N

Solving the equation, we find the speed of the wave:

v=\frac{1}{2(0.72)}\sqrt{\frac{84.1}{0.0042/0.72}}=83.4 m/s

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

5 0
3 years ago
A car of mass 1200 kg, moving with a speed of 72 mph on a highway,
Keith_Richards [23]

momentum(p) = mass(m) x velocity(v)

KE = kinetic energy = 1/2 mv²

a.

the ratio of the momentum of the SUV to that of the car

\tt \dfrac{mv}{1.5m\dfrac{2}{3}v }=1:1

b.  the ratio of the KE of the SUV to that of the car

\tt \dfrac{1/2\times mv^2}{1/2\times 1.5m\times (\dfrac{2}{3}v )^2}=\dfrac{mv^2}{1.5m\dfrac{4}{6}v^2 }=1:1

8 0
2 years ago
A sealed cubical container 10.0 cm on a side contains three times Avogadro's number of molecules at a temperature of 24.0°C. Fin
rodikova [14]

This question involves the concepts of general gas equation and pressure.

The force exerted by the gas on one of the walls of the container is "74.08 KN".

First, we will use the general gas equation to find out the pressure of the gas:

PV = nRT

where,

P = Pressure of the gas = ?

V = Volume of cube = (side length)³ = (10 cm)³ = (0.1 m)³ = 0.001 m³

n = no. of moles = 3 (since molecules equal to avogadro's number make up 1 mole)

R = general gas constant = 8.314 J/mol.K

T = Absolute Temperature = 24°C + 273 = 297 K

Therefore,

P = \frac{(3)(8.314\ J/mol.k)(297\ K)}{0.001\ m^3}

P = 7407.78 KPa

Now, the force on one wall can be given as follows:

P =\frac{F}{A}\\\\F=PA

where,

A = area of one wall = (side length)² = (0.1 m)² = 0.01 m²

Therefore,

F=(7407.78\ KPa)(0.01\ m^2)\\

<u>F = 74.08 KN</u>

<u></u>

Learn more about the general gas equation here:

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5 0
2 years ago
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