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nasty-shy [4]
3 years ago
8

The state of matter that consists of electrically charged particles

Physics
1 answer:
hjlf3 years ago
6 0
The state of matter that consists of electrically charged particles is Plasma.
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What does MA mean for you in real life?
andrezito [222]
To me "Ma" mean in real life is either mama or Massachusttes.
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An imaginary line perpendicular to a reflecting surface is called ____refrac_____.
umka2103 [35]
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What do the best conductors have in common?
tensa zangetsu [6.8K]

Answer:

A super conductor is a perfect conductor that has zero resistance. It doesn't just have very low resistance and conducts electricity well, it has ZERO resistance and conducts electricity perfectly with no losses at all

6 0
2 years ago
Read 2 more answers
You throw a glob of putty straight up toward the ceiling, which is 3.60 m above the point where the putty leaves your hand. The
Sliva [168]

Answer:

Explanation:

Given

Height of ceiling is h=3.6\ m

Initial speed of Putty u=9.5\ m/s

Speed of Putty just before it strike the ceiling is given by

v^2-u^2=2as

where v=final velocity

u=initial velocity

a=acceleration

s=displacement

v^2-9.5^2=2\times (-9.8)\times 3.6

v^2=19.69

v=4.43\ m/s

time taken by putty to reach the ceiling

v=u+at

4.43=9.5-9.8\times t

t=\frac{5.07}{9.8}

t=0.517\ s

8 0
3 years ago
A 0.500-nm x-ray photon is deected through 134 in a Compton scattering event. At what angle (with respect to the incident beam)
natita [175]

Answer:

The angle of recoil electron with respect to incident beam of photon is 22.90°.

Explanation:

Compton Scattering is the process of scattering of X-rays by a charge particle like electron.

The angle of the recoiling electron with respect to the incident beam is determine by the relation :

\cot\phi = (1+\frac{hf}{m_{e}c^{2}  })\tan\frac{\theta }{2}      ....(1)

Here ∅ is angle of recoil electron, θ is the scattered angle, h is Planck's constant, m_{e} is mass of electron, c is speed of light and f is the frequency of the x-ray photon.

We know that, f = c/λ      ......(2)

Here λ is wavelength of x-ray photon.

Rearrange equation (1) with the help of equation (1) in terms of  λ .

\cot\phi = (1+\frac{h}{m_{e}c\lambda  })\tan\frac{\theta }{2}

Substitute 6.6 x 10⁻³⁴ m² kg s⁻¹ for h, 9.1 x 10⁻³¹ kg for m_{e}, 3 x 10⁸ m/s for c, 0.500 x 10⁻⁹ m for λ  and 134° for θ in the above equation.

\cot\phi = (1+\frac{6.6\times10^{-34} }{9.1\times10^{-31}\times3\times10^{8}\times0.5\times10^{-9}  })\tan\frac{134 }{2}

\cot\phi=2.37

\phi = 22.90°

8 0
3 years ago
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