1.8 mol of Na. hope this helps
In the given graph, from 4.0 s to 8.0 s, the object is at rest because the speed is zero.
In the given graph we can deduce the following;
- at the time interval, 0 s to 3.5 s, the speed of the object = 1 cm/s
- when the time, t= 4 s, the <em>speed</em> of the object = 0 cm/s
- at the time interval, 4.0 s to 8.0 s, the<em> speed </em>of the object = 0 cm/s
When the <em>speed</em> of an object is zero (0), the object is simply at rest.
Thus, we can conclude that in the given graph, from 4.0 s to 8.0 s, the object is at rest because the speed is zero.
Learn more here:brainly.com/question/10454047
Answer:
331.7m/s
Explanation:
Given parameters:
Initial velocity = 100m/s
Acceleration = 50m/s²
Distance = 1km = 1000m
Unknown:
Final velocity = ?
Solution:
To solve this problem, we have to apply the right motion equation shown below;
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Now insert the parameters and solve;
v² = 100² + (2 x 50 x 1000)
v² = 110000
v = √110000 = 331.7m/s
Answer:
Time and velocity
Explanation:
The time taken for the velocity to double is very important to find the amount of acceleration the car acquires.
Acceleration is the rate of change of velocity with time.
Acceleration = 
v is the initial velocity
u is the final velocity
t is the time taken
So, the velocity and time is needed to calculate the value of the acceleration the car undergoes.
