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natali 33 [55]
4 years ago
9

Label the chemical equation.

Chemistry
1 answer:
labwork [276]4 years ago
5 0

Answer:

Kindly check Explanation

Explanation:

Given the chemical equation:

2 Mg(s) + O2(g) → 2 MgO(s)

2 molecules of Magnesium + Oxygen gas (Reactant)

→ ( yield)

2 molecules of magnesium oxide (product)

2 in Mg and MgO (coefficients)

2 in Oxygen gas (subscript)

Solid (s) - physical state of Reactant Mg

Gas (g) - physical state of Reactant O2

Solid (s) - physical state of product 2MgO

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Answer: fourth option, 10.8 kJ


Explanation:


The <em>heat of fusion</em>, also named latent heat of fusion, is the amount of heat energy required to change the state of a substance from solid to liquid (at constant pressure).


The data of the <em>heat of fusions</em> of the substances are reported in tables and they can be shown either per mole or per gram of substance.


In this case we have that the<em> heat of fusion for water </em>is reported per mole: <em>6.02 kJ/mole</em>.


The formula to calculate <em>how many kJ of heat (total heat) are needed to completely melt 32.3 g of water, given that the water is at its melting point</em> is:

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The calculations are:

  • number of moles = mass / molar mass

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When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

<h3>What is Limiting reagent ?</h3>

Limiting reagents are the substances that are completely consumed first in a chemical reaction.

Given ;

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Given equation ;

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If 2 mole Zn produces : 2 moles of ZnO (According to given balanced equation)

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1 mole of Zn will produce = 2/2 x 1

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Hence, When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.

Learn more about Limiting reagent here ;

brainly.com/question/11848702

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Chemical Quantities "Molar Mass - 2 step" - Wksh #3 Directions: Use dimensional analysis to perform the following calculations.
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There are about 1.27  × 10^23 molecules present in 13.5 g of SO2.

<h3>What are molecules?</h3>

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6.02 × 10^23 formula units of Fe2O3 has a mass of 160 g

8.83 x 10^23 formula units of Fe2O3 has a mass of 8.83 x 10^23 x 160 g/6.02 × 10^23

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