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Sveta_85 [38]
2 years ago
10

Consider the following reversible reaction.

Chemistry
2 answers:
Marina86 [1]2 years ago
7 0

Answer:

B is the correct option

Explanation:

K= the ratio of product of concentration of products to the product of concentration of reactants raised to power equal to their cofficients.

Fofino [41]2 years ago
6 0

Answer:

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Explanation:aaaaaaa

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From the following balanced equation,
ArbitrLikvidat [17]

Answer:

9.72 grams.

Explanation:

From the equation, 4 moles of NH₃ produce 6 moles of  water.

Therefore the reaction to product ratio of  NH₃ to H₂O is 4:6

and 2:3 into its simplest form.

The number of moles of NH₃ in 6.12 g is:

Number of moles=mass/ RMM

=6.12 g/17 G/mol

=0.36 moles.

Therefore the number of moles of H₂O produced is calculated as follows.

(0.36 Moles×3)2 = 0.54 moles

Mass= Number of moles × RMM

=0.54 moles×18g/mol

=9.72 grams.

6 0
3 years ago
Unrestricted populations of organisms experience _____.
Fudgin [204]
Unrestricted populations of organisms experience Exponential growth. 

As a population reaches is carrying capacity there is an increase in competition for All of the above.
 Hope I helped. 
5 0
2 years ago
Read 2 more answers
Electronegativity is defined as a measure of the tendency of atoms to attract electrons in a chemical bond.
stira [4]
True.......................................
4 0
2 years ago
How many valence electrons are in each atom? <br> a. potassium b. carbon c. magnesium d. oxygen
Alona [7]
A. 1 valence electron
b. 4 valence electrons
c. 2 valence electrons
d. 6 valence electrons
8 0
2 years ago
You are performing a titration of a triprotic acid, when you spill water on your lab notebook. you can read that: pka 1 = 1.40,
eimsori [14]
According to the PH formula:
PH= Pka +㏒ [strong base/weak acid]
when we have PH at the first equivalence =3.35 and the Pka1 = 1.4
So, by substitution, we can get the value of ㏒[strong base / weak acid]
3.35 = 1.4 + ㏒[strong base/ weak acid]
∴㏒[strong base/weak acid] = 3.35-1.4 = 1.95 
to get the Pka2 we will substitute with the value of ㏒[strong base/ weak acid] and the value of PH of the second equivalence point
∴Pk2 = PH2 - ㏒[strong base/ weak acid]
          = 7.55 - 1.95 = 5.6 
5 0
3 years ago
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