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kicyunya [14]
3 years ago
11

Iron(III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 25.9 g of Fe reacts

completely with oxygen? 4Fe(s) + 3O2(g) ---> 2Fe2O3(s)
A.12.0g B. 25.0g C. 37.0g D. 49.0g
Chemistry
2 answers:
zhuklara [117]3 years ago
6 0
The balanced chemical reaction would be

<span>4Fe(s) + 3O2(g) ---> 2Fe2O3(s) 

We are given the amount of Fe to be used in the reaction. We use this as the starting point for the calculations. We do as follows:

25.9 g Fe (1 mol / 55.85 g) ( 2 mol Fe2O3 / 1 mol Fe ) (159.69 g / mol ) = 262.48 g Fe2O3 produced</span>
azamat3 years ago
5 0

Answer: The correct answer is actually B. 23.9

Explanation:

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7 0
1 year ago
2 A(g) + B(g) ---&gt; 2 C(g)Rate = k [A][B]At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The obse
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Lmol⁻¹s⁻¹

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The rate law of the given reaction is:-

Rate=k[A][B]

Wherem, k is the rate constant.

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