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kicyunya [14]
3 years ago
11

Iron(III) oxide is formed when iron combines with oxygen in the air. How many grams of Fe2O3 are formed when 25.9 g of Fe reacts

completely with oxygen? 4Fe(s) + 3O2(g) ---> 2Fe2O3(s)
A.12.0g B. 25.0g C. 37.0g D. 49.0g
Chemistry
2 answers:
zhuklara [117]3 years ago
6 0
The balanced chemical reaction would be

<span>4Fe(s) + 3O2(g) ---> 2Fe2O3(s) 

We are given the amount of Fe to be used in the reaction. We use this as the starting point for the calculations. We do as follows:

25.9 g Fe (1 mol / 55.85 g) ( 2 mol Fe2O3 / 1 mol Fe ) (159.69 g / mol ) = 262.48 g Fe2O3 produced</span>
azamat3 years ago
5 0

Answer: The correct answer is actually B. 23.9

Explanation:

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When the following reaction is completed and written in the form of a net ionic equation, which of the following elements will N
Alex Ar [27]

Answer:

d. N

Explanation:

Chemical equation:

Pb(NO₃)₂(aq)  + K₂SO₄(aq)  →  PbSO₄(s) + KNO₃(aq)

Balanced Chemical equation:

Pb(NO₃)₂(aq)  + K₂SO₄(aq)  → PbSO₄(s) + 2KNO₃(aq)

Ionic equation:

Pb²⁺(aq) + 2NO₃⁻(aq)  + 2K⁺(aq) + SO₄²⁻(aq)  → PbSO₄(s) + 2K⁺(aq) + 2NO₃⁻(aq)

Net ionic equation:

Pb²⁺(aq) + SO₄²⁻(aq)  → PbSO₄(s)

The NO₃⁻(aq) and K⁺(aq)are spectator ions that's why these are not written in net ionic equation. The PbSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

4 0
2 years ago
An aqueous potassium iodate (KIO3) solution is made by dissolving 553 grams of KIO3 in sufficient water so that the final volume
liberstina [14]

Answer:

M KIO3 = 1.254 mol/L

Explanation:

  • molarity (M) [=] mol/L

∴ w KIO3 = 553 g

∴ mm KIO3 = 214.001 g/mol

∴ volumen sln = 2.10 L

⇒ mol KIO3 = (553 g)×(mol/210.001 g) = 2.633 mol

⇒ M KIO3 = (2.633 mol KIO3 / (2.10 L sln)

⇒ M KIO3 = 1.254 mol/L

3 0
3 years ago
Read 2 more answers
This is an impossible formula. Pretend it is real.
guapka [62]

There are eight moles of oxygen atoms  in 1 mole of Mn_{9}(ClO_{4}) _{2}.

<h3>What is the number of moles of oxygen atoms?</h3>

We know that a compound is composed of atoms. The atoms that make up the molecule are chemically combined. It is usual that the number of atoms in the compound would correspond with the chemical formula.

Now we have the compound  Mn_{9}(ClO_{4}) _{2}. In one mole of the compound we have;

  • 9 Moles of manganese atom
  • 2 moles of chlorine atom
  • 8 moles of oxygen atom

Thus, there are eight moles of oxygen atoms  in 1 mole of Mn_{9}(ClO_{4}) _{2}.

Learn more about atoms;brainly.com/question/1566330

#SPJ1

7 0
1 year ago
Let this be an easy 5 points for your brainly account all is ask for in return is a "thank you"
Svet_ta [14]

Answer:

The number of neutrons present in one atom of isotope of Silicon of mass 28 amu is<u> 14 neutrons</u>

Explanation:

Symbol of Si isotope

_{14}^{28}\textrm{Si}

<u>Number of Neutron = Mass number - Atomic Number</u>

Mass number = Total number of protons and neutrons present in the nucleus of the atom.For Si = 28 amu

Atomic Number = Total number of Protons present in the nucleus.

Si = 14

Number of neutron = 24 - 14

                                = 14

4 0
3 years ago
What is the bond order of li2−? express the bond order numerically?
jeka94
Atomic Number of Lithium is 3, so it has 3 electrons in its neutral state. Also, Li₂ will have 6 electrons. But the chemical formula we are given has a negative charge on it (i.e Li₂⁻) so there is an additional electron (RED) present on this compound. So, the total number of electrons are 7. The MOT diagram for this compound is shown below. According to diagram we are having 4 electrons in Bonding Molecular Orbitals (BMO) and 3 electrons in Anti-Bonding Molecular Orbitals (ABMO). Bond Order is calculated as,

              Bond Order  =  (# of e⁻s in BMO - # of e⁻s in ABMO) ÷ 2

              Bond Order  =  (4 - 3) ÷ 2

              Bond Order  =  1 ÷ 2
Or,
              Bond Order  =  1/2
Or,
              Bond Order  =  0.5

4 0
3 years ago
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