1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natalija [7]
3 years ago
9

17.Observe the given figure carefully-

Chemistry
1 answer:
SpyIntel [72]3 years ago
7 0
A brings light together and B spreads it out. A is convex and B is concave.
You might be interested in
Compute 4.659×104−2.14×104. Round the answer appropriately.
erma4kov [3.2K]
261.976 which rounds to 261.98(if rounding to the hundredths.
6 0
3 years ago
A sailboat is pushed by a steady wind with a force of 4000 N. Its acceleration is 2
AveGali [126]

Answer:

<h2>2000 kg</h2>

Explanation:

The mass of the sailboat can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{4000}{2}  \\

We have the final answer as

<h3>2000 kg</h3>

Hope this helps you

6 0
3 years ago
What is force?.......<br><br>​
snow_tiger [21]

<em>Force is a push or pull which changes or tend to change the position of a body...</em>

4 0
3 years ago
Read 2 more answers
What is the concentration of an alcl3 solution if 150. ml of the solution contains 550. mg of cl- ion?
valina [46]

The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M


calculation


concentration = moles /volume in liters


volume in liters = 150 /1000= 0.15 L


number of moles calculation

write the equation for dissociation of Al2Cl3

that is AlCl3 ⇔ Al^3+ + 3 Cl ^-


find the moles of Cl^- formed

moles =mass/molar mass

mass in grams= 550/ 1000 =0.55 grams

molar mass of Cl^- =35.5 g/mol


moles is therefore= 0.55/35.5 =0.0155 moles


by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles



concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M

6 0
3 years ago
Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit
vfiekz [6]

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

For H_2SO_4:-  

Mass of H_2SO_4 = 196 g

Molar mass of H_2SO_4 = 98 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{196\ g}{98\ g/mol}

Moles\ of\ Sulfuric\ acid= 2\ mol

According to the given reaction:

2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,  

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = 4\times 40\ g = 160 g</u>

7 0
3 years ago
Other questions:
  • A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the ca
    11·1 answer
  • 1‑Propanol ( P ∘ 1 = 20.9 Torr at 25 ∘ C ) and 2‑propanol ( P ∘ 2 = 45.2 Torr at 25 ∘ C ) form ideal solutions in all proportion
    6·2 answers
  • Gerry is looking at salt under a powerful microscope and notices a crystalline structure. What can be known about
    13·1 answer
  • The Constitution gives which of the following powers to the Vice President?
    11·2 answers
  • How much heat is needed to raise the temperature of 20.0g of H2O by 10.6oC?
    8·1 answer
  • Which of the following terms is NOT the name of the body system pictured above?
    7·1 answer
  • What do you think a mutation is?
    5·1 answer
  • Could someone plz help me? Giving brainliest
    6·1 answer
  • A balloon that can hold 85 L of air is inflated with 3.5 moles of gas at a pressure of 1.0 atmosphere. What is the temperature o
    8·1 answer
  • Commercial products commonly report concentration in terms of "percentage." Using this
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!