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3 years ago

17.Observe the given figure carefully-

Chemistry

1 answer:

SpyIntel [72]3 years ago

7 0

A brings light together and B spreads it out. A is convex and B is concave.

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Compute 4.659×104−2.14×104. Round the answer appropriately.

erma4kov [3.2K]

261.976 which rounds to 261.98(if rounding to the hundredths.

6 0

3 years ago

A sailboat is pushed by a steady wind with a force of 4000 N. Its acceleration is 2

AveGali [126]

Answer:

Explanation:

The mass of the sailboat can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{4000}{2} \\$

We have the final answer as

Hope this helps you

6 0

3 years ago

What is force?.......<br><br>

snow_tiger [21]

<em>Force is a push or pull which changes or tend to change the position of a body...</em>

4 0

3 years ago

Read 2 more answers

What is the concentration of an alcl3 solution if 150. ml of the solution contains 550. mg of cl- ion?

valina [46]

The concentration of AlCl3 solution if 150 ml of the solution contains 550 mg of cl- ion is 0.0344 M

calculation

concentration = moles /volume in liters

volume in liters = 150 /1000= 0.15 L

number of moles calculation

write the equation for dissociation of Al2Cl3

that is AlCl3 ⇔ Al^3+ + 3 Cl ^-

find the moles of Cl^- formed

moles =mass/molar mass

mass in grams= 550/ 1000 =0.55 grams

molar mass of Cl^- =35.5 g/mol

moles is therefore= 0.55/35.5 =0.0155 moles

by use of mole ration betweem AlCl3 to Cl^- which is 1:3 the moles of AlCl3 is =0.0155 x 1/3= 5.167 x10^-3 moles

concentration of AlCl3 is therefore= 5.167 x10^-3/ 0.15 =0.0344 M

6 0

3 years ago

Given the reaction to 2NaOH + H2 SO4 â Na2 SO4 + 2H2 O, what is the total number of grams of NaOH needed to react completely wit

vfiekz [6]

Answer:

4 moles, 160 g

Explanation:

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

For $H_2SO_4$ :-

Mass of $H_2SO_4$ = 196 g

Molar mass of $H_2SO_4$ = 98 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{196\ g}{98\ g/mol}$

$Moles\ of\ Sulfuric\ acid= 2\ mol$

According to the given reaction:

$2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

1 mole of sulfuric acid reacts with 2 moles of NaOH

So,

2 moles of sulfuric acid reacts with 2*2 moles of NaOH

Moles of NaOH must react = 4 moles

Molar mass of NaOH = 40 g/mol

<u>Mass = Moles*molar mass = $4\times 40\ g$ = 160 g</u>

7 0

3 years ago