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aleksandr82 [10.1K]

4 years ago

15

Which of the following is the weakest?. . A. polar covalent bond. . B. dipole interaction. . C. ionic bond

2 answers:

taurus [48]4 years ago

8 0

The weakest bond is the dipole interaction. Dipole-dipole interactions occur when two dipolar molecules interact with each other through space. When a dipole interaction occurs, the partially negative portion of one of the polar molecules is attracted to the partially positive portion of another polar molecule.

Trava [24]4 years ago

8 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

From the given options:

<u>Option A:</u> polar covalent bond

Polar covalent bond is defined as the bond which is formed when there is difference in electronegativity between the atoms forming a bond. For Example: HCl, the bond between the hydrogen and chloride element is a polar covalent bond.

<u>Option B:</u> dipole interaction

Dipole-dipole interactions are occured when partial charges are formed in one molecule and are attracted to the oppositely partial charge in a molecule which is present nearby. This bond is the weakest of all.

<u>Option C:</u> ionic bond

This bond is formed when a complete transfer of electrons takes place from one atom to another atom. Ions are formed during this reaction. Thus, this bond formed is the strongest.

The bond strength order follows:

$\text{Ionic bond}>\text{Polar covalent bond}>\text{Dipole-dipole interactions}$

Hence, the correct answer is Option B.

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Na2O + HCl -> NaCl + H2O

Charra [1.4K]

Na2O + HCl→ NaCl +H2O

Does the equation above satisfy the law of mass conservation of matter.

No, since there are two sodium atoms as reactants, but only one sodium atom as a product.

<em><u>Explanation</u></em>

According to the law of mass conservation the number of atoms in the reactant side must be equal to the number of atoms in the product side.

For this reason the equation above does not satisfy the law of mass conservation since the number of sodium atoms are not equal in both side.

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Andrej [43]

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3 years ago

Read 2 more answers

Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the

Alecsey [184]

Explanation:

The chemical equation is as follows.

$\frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)$

And, the given enthalpy is as follows.

$\frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g)$ ; $\Delta H$ = 102.5 kJ

Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

$\Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}$

102.5 = $[(\frac{1}{2})x + 498] - [(2)(243)]$

102.5 = $(\frac{1}{2})x + 498 - 486$

102.5 - 12 = $\frac{x}{2}$

x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

$\Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})$

x = $[(\frac{1}{2})181 + (\frac{1}{2})498] - 243$

= 339.5 - 243

= 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

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Answer:

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Explanation:

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