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KIM [24]
3 years ago
10

What happens during every chemical change?

Chemistry
2 answers:
Aneli [31]3 years ago
6 0
The chemical make-up changes.
Alexeev081 [22]3 years ago
3 0
The molecules in the reactants interact to form new substances. In a physical change, like a state change or dissolving, no new substance is formed. Explain that another way to say that no atoms are created or destroyed in a chemical reaction is to say, “Mass is conserved.”
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What is the empirical formula of a compound containing carbon, hydrogen, and oxygen in the ratio 14:42:84? C14H42O84
kati45 [8]
C:H:O = 14:42:84 = 7:21:42 = 1:3:6

CH₃O₆
6 0
4 years ago
Read 2 more answers
Isn’t urgent the first 3 will be marked BRAINIEST
bearhunter [10]

Answer:

Al2(SO4)3 and Mg(OH)2

Explanation:

1. Al has a charge of 3-, and SO4 of 2-

when you cross multiply the charges you get

Al2 and (SO4)3

*the reason theres a bracket around the sulfate ion is that the charge 3 is not for oxygen only, but the entire sulphate ion*

Hence, Al2(SO4)3

2. Mg has a charge of 2- and OH of 1-

again cross multiply

Mg (you dont need to add the 1) and (OH)2

again, the bracket around OH means the charge appiles to Oxygen AND hydrogen

hence, Mg(OH)2

7 0
3 years ago
Read 2 more answers
Consider a solution containing .100 M fluoride ions and .126M hydrogen fluoride. The concentration of fluoride ions after the ad
S_A_V [24]
Given:

Concentration of Fluoride ions = 0.100 M
Concentration of Hydrogen Fluoride = 0.126 M

Asked: Concentration of fluoride ions after the addition of 5ml of 0.0100 M HCl to 25 mL of the solution

Assume: 50:50 ratio of fluoride ions and HF

12.5ml*0.1mol/L *1L/1000mL + 12.5*0.126mol/L * 1L/1000mL = 2.825x10^-3 moles F-

5ml * 0.01 mol/L *1L/1000mL = 5x10^-5 moles

Assume: Volume additive

Final concentration = 2.825x10^-3 + 5x10^-5 moles/ 30 ml * 1000ml/L =0.0958 M
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3 0
3 years ago
Which 3 elements had complete out shells? (you will probably need to use the periodic table)
wlad13 [49]
The inert gases like neon,argon ,krypton have complete shells
3 0
3 years ago
If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
klemol [59]
Let us start with the total area of the lawn. Area= width x length, ie, 21 x 20 = 420 sq. ft.   Snow flakes per square foot per minute = 1350  So Snow flakes for 420 sq.feet per minute = 420 x 1350 = 567000.   Snow flakes for 1 hour = 567000 x 60 = 34020000 (60 minutes)  Weight of 34020000 snow flakes = 34020000 x 1.60 = 54432000mg.  To convert it into kilograms, divide this number by 1000000 (1 kilogram = 1000000 milligrams)  Thus 54432000/1000000 = 54.432 kilograms or 54 kilograms and 432 grams.
6 0
3 years ago
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