Question

Two trains, each having a speed of 25 lem are headed at each other on the same straight track. A bird that can fly 60 l'm flies off the front of one train when they hr are 8km apart and heads directly for the other train. On reaching the other train, the bird flies directly back to the first train, and so forth. (We have no idea why a bird would behave in this way.) Calculate the total distance the bird travels before the trains collide?

Answer 1

The total distance the bird travels before the trains collide is 9.6 km.

Time taken before the two trains meet each other

Apply the principle of relative velocity as shown below;

(Speed of train A minus Speed of train B)(time before they meet) = distance between them

(Va - Vb)t = d

• let the direction of the train moving rightward = positive
• let the direction of the train moving leftward = negative

speed of train a = + 25 km/h

speed of train b = - 25 km/h

(25 km/h - - 25 km/h)t = 8 km

(50 km/h)t = 8 km

t = 8 km / 50 km/h

t = 0.16 h

Distance traveled by the bird

Since the bird is in steady motion, the distance covered within the time two trains meet is calculated as follows;

d = speed of bird x time

d = 60 km/h x 0.16 h

d = 9.6 km

Thus, the total distance the bird travels before the trains collide is 9.6 km.

Learn more about distance here: brainly.com/question/2854969

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