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djverab [1.8K]
3 years ago
9

Mileposts mark distance along a highway. A car traveled from milepost 15 to milepost 185. To calculate the average speed of the

car, what additional information is necessary? the minimum and maximum speeds of the car the initial and final speeds of the car the time of the journey the total length of the highway
Physics
1 answer:
Marina CMI [18]3 years ago
6 0
Speed = (distance covered) / (time to cover the distance).

You know the distance covered ...  Sign 15 to sign 185 = 170 miles .

Now, to calculate the car's average speed, you need to know
how long it took him to cover the distance. 

That's "the time of the journey". 
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The safe load, L, of a wooden beam supported at both ends varies jointly as the width, w, the square of the depth, d, and invers
soldier1979 [14.2K]

Answer:

L' = 555.95 lb

Explanation:

Analyzing the given conditions in the question, we get

The safe load, L is directly proportional to width (w) and square of depth (d²)

 also,

L is inversely proportional length (l) i.e L = k/l

combining the above conditions, we get an equation as:

 L = k(wd²/l)

 now, for the first case we have been given

w = 3 in

d = 6 in

l = 11 ft

L = 1213 lbs

 thus,

1213 lb = k ((3 × 6²)/11)

or

k = 123.54 lbs/(ft.in³)  

Now,

Using the calculated value of k to calculate the value of L in the second case  

in the second case, we have

w = 6 in

d =3 in

l = 12 ft

Final Safe load L' =  123.54 × (6 × 3²/12)

or

L' = 555.95 lb

6 0
3 years ago
A 4.40-m-long, 500 kg steel uniform beam extends horizontally from the point where it has been bolted to the framework of a new
icang [17]

Answer:

Torque=13798.4 N.m

Explanation:

Given data

Mass of beam m₁=500 kg

Mass of the person m₂=70 kg

length of steel r₁=4.40m

center of gravity of the beam is at r₂=r₁/2 =4.40/2 = 2.20m

To find

Torque

Solution

Torque due to beam own weight

T_{1}=m_{1}gr_{1}\\ T_{1}=500*2.2*9.8\\T_{1}=10780N.m

Torque due to person

T_{2}=m_{2}r_{2}g\\T_{2}=70*(4.40)*(9.8)\\T_{2}=3018.4 N.m

Now for total torque

T_{total}=T_{1}+T_{2}\\T_{total}=10780+3018.4\\T_{total}=13798.4N.m

4 0
3 years ago
If F1 is the magnitude of the force exerted
aleksandrvk [35]

Answer: 3. F1 = F2

Explanation:

According to <u>Newton's law of Gravitation</u>, the force F exerted <u>between two bodies</u> or objects of masses M and m and separated by a distance r is equal to the product of their masses divided by the square of the distance:  

F=G\frac{Mm}{r^2} (1)

Where Gis the gravitational constant

Now, in the especific case of the Earth and the satellite, where the Earth has a mass M and satellite a mass m, being both separated a distance r, the force exerted  by the Earth on the satellite is:

F1=G\frac{Mm}{r^2}   (2)

And the force  exerted by the satellite on the Earth is:

F2=G\frac{Mm}{r^2}   (3)

As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

F1=F2

3 0
3 years ago
If a sample emits 2000 counts per second when the detector is 1 meter from the sample, how many counts per second would be obser
Alona [7]

Answer:

<h2><em>6000 counts per second</em></h2>

Explanation:

If a sample emits 2000 counts per second when the detector is 1 meter from the sample, then;

2000 counts per second = 1 meter ... 1

In order to know the number of counts per second that would be observed when the detector is 3 meters from the sample, we will have;

x count per second = 3 meter ... 2

Solving the two expressions simultaneously for x we will have;

2000 counts per second = 1 meter

x counts per second = 3 meter

Cross multiply to get x

2000 * 3 = 1* x

6000 = x

<em></em>

<em>This shows that 6000 counts per second would be observed when the detector is 3 meters from the sample</em>

5 0
3 years ago
As the sun sets on horizon, its rays are____ by the ocean water
valentinak56 [21]

Answer:

Reflected

Explanation:

I do not have much context here, but reflection is what happens when the sun sets on the water. The rays hit the surface of the water and bounce off, known as refelction.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

5 0
3 years ago
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