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djverab [1.8K]
3 years ago
9

Mileposts mark distance along a highway. A car traveled from milepost 15 to milepost 185. To calculate the average speed of the

car, what additional information is necessary? the minimum and maximum speeds of the car the initial and final speeds of the car the time of the journey the total length of the highway
Physics
1 answer:
Marina CMI [18]3 years ago
6 0
Speed = (distance covered) / (time to cover the distance).

You know the distance covered ...  Sign 15 to sign 185 = 170 miles .

Now, to calculate the car's average speed, you need to know
how long it took him to cover the distance. 

That's "the time of the journey". 
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Light travels in waves AND in bundles called "photons".

It's hard to imagine something that's a wave and also a bundle.
But it turns out that light behaves like both waves and bundles.

If you design an experiment to detect waves, then it responds to light.

And if you design an experiment to detect 'bundles' or particles, then
that one also responds to light.
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Why would a soccer ball keep going forever without physics? Pls help and explain why
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erastova [34]

Answer:

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Explanation:

4 0
3 years ago
A stretched string has a mass per unit length of 4.87 g/cm and a tension of 16.7 N. A sinusoidal wave on this string has an ampl
Burka [1]

Answer:

Explanation:

Given that,

Mass per unit length is

μ = 4.87g/cm

μ=4.87g/cm × 1kg/1000g × 100cm/m

μ = 0.487kg/m

Tension

τ = 16.7N

Amplitude

A = 0.101mm

Frequency

f = 71 Hz

The wave is traveling in the negative direction

Given the wave form

y(x,t) = ym• Sin(kx + ωt)

A. Find ym?

ym is the amplitude of the waveform and it is given as

ym = A = 0.101mm

ym = 0.101mm

B. Find k?

k is the wavenumber and it can be determined using

k = 2π / λ

Then, we need to calculate the wavelength λ using

V = fλ

Then, λ = V/f

We have the frequency but we don't have the velocity, then we need to calculate the velocity using

v = √(τ/μ)

v = √(16.7/0.487)

v = 34.29

v = 5.86 m/s

Then, we can know the wavelength

λ = V/f = 5.86 / 71

λ = 0.0825 m

So, we can know the wavenumber

k = 2π/λ

k = 2π / 0.0825

k = 76.18 rad/m

C. Find ω?

This is the angular frequency and it can be determined using

ω = 2πf

ω = 2π × 71

ω = +446.11 rad/s

D. The angular frequency is positive (+) because the direction of propagation of wave is in the negative direction of x

5 0
2 years ago
Richard is driving home to visit his parents. 150 mi of the trip are on the interstate highway where the speed limit is 65 mph .
Serggg [28]

Answer:

t = 25.5 min

Explanation:

To know how many minutes does Richard save, you first calculate the time that Richard takes with both velocities v1 = 65mph and v2 = 80mph.

t_1=\frac{x}{v_1}=\frac{150mi}{65mph}=2.30h\\\\t_2=\frac{x}{v_2}=\frac{150mi}{80mph}=1.875h

Next, you calculate the difference between both times t1 and t2:

\Delta t=t_1-t_2=2.30h-1.875h=0.425h

This is the time that Richard saves when he drives with a speed of 80mph. Finally, you convert the result to minutes:

0.425h*\frac{60min}{1h}=25.5min=25\ min\ \ 30 s

hence, Richard saves 25.5 min (25 min and 30 s) when he drives with a speed of 80mph

3 0
2 years ago
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